Is there like a pic for it
5x^2 + 7x = 6
5x^2 + 7x -6 = 0
5x^2 + 10x -3x -6 =0
5x × (x + 2) -3 (x + 2) = 0
(x + 2) × (5x - 3) = 0
x + 2 = 0
5x - 3 = 0
x = -2
x = 3/5
answer: x = -2, x = 3/5
Answer:
1/3
Step-by-step explanation:
12-8=4
4/12 = 1/3
Answer:
If you're solving for x, the answer is -50. x = -50
Step-by-step explanation:
Remove the parenthesis and distribute:
-5(x-8) + 7(x+3) = x + 11
-5x + 40* + 7(x+3) = x + 11
-5x + 40 +7x + 21* = x + 11
Collect like terms and calculate:
| -5x + 7x
2x + 40 + 21 = x + 11
| 40 + 21
2x + 61 = x + 11
Move them to the other side like so:
2x - x* + 61 = 11
| -61
2x - x = 11 - 61
Combine:
x = 11 - 61
x = -50
<span>Mean absolute deviation around the mean
</span>Mean for set 1 equals: (20+24+40+63+76+89)/6 = 312/6 = 52
Mean for set 2 equals: (41+50+58+62+72+83)/6 = 366/6 = 61
Mean absolute deviation around the mean for set 1 equals:
( |20 - 52| + |24 - 52| + |40 - 52| + |63 - 52| + |76 - 52| + |89 - 52| )/6 = (32 + 28 + 12 + 11 + 24 + 37)/6 = 144/6 = 24
Mean absolute deviation around the mean for set 2 equals:<span>
</span>( |41 - 61| + |50 - 61| + |58 - 61| + |62 - 61| + |72 - 61| + |83 - 61| )/6 = (20 + 11 + 3 + 1 + 11 + 22)/6 = 68/6 = 11,334
MAD for City 2 is bigger than the MAD for City 1, which means the average monthly temperatures of City 2 vary more than the average temperatures for City 1
