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erica [24]
3 years ago
12

Help with 2 plz I really need help

Mathematics
1 answer:
Kazeer [188]3 years ago
4 0

the whole triangle is call an acute equilibrium triangle if that's the answer your looking for if not I need to see the whole question


You might be interested in
Which of the following sets are continuous? Please help
Alecsey [184]

Answer:

A, C and D are continuous

Step-by-step explanation:

A is a set of any number x which 30 < x <=45

B is a set that contains only 3 and 7

C is a set of any number x which 60 <= x < 100

D is a set of any number x which -infinity < x < + infinity

E is a set that contains only even whole numbers

A continuous data set is a quantitative data set representing a scale of measurement that can consist of numbers other than whole number, like decimals and fractions.

7 0
3 years ago
A circus acrobat is shot out of a cannon. The equation for the acrobat's pathway can be modeled by h= -16t^2+25. How long will i
Alex_Xolod [135]
For this we almost have the following equation:
 h = -16t ^ 2 + 25&#10;
 We must match the equation to zero:
 -16t ^ 2 + 25 = 0&#10;
 From here, we clear the value of t.
 We have then:
 16t ^ 2 = 25&#10;&#10;t ^ 2 = 25/16
 We discard the negative root because we are looking for time:
 t =  \sqrt{ \frac{25}{16} } &#10;&#10;
 t =  \frac{5}{4}
 Answer:
 
it will take him to reach the ground about:
 
t = \frac{5}{4} seconds
5 0
3 years ago
W(t) = 3t – 1; t = 5
son4ous [18]
I’m not sure if your asking for the solution, but Hope this helps!

8 0
3 years ago
How many candy bars did Aaliyah start with if she sold them at a constant rate
nikklg [1K]
We can’t answer this because we don’t have the numbers
3 0
3 years ago
I have the question in a screengrab. Thank you, whoever helps me.
nata0808 [166]

To simplify

\sqrt[4]{\dfrac{24x^6y}{128x^4y^5}}

we need to use the fact that

\sqrt[4]{x^4}=|x|

Why the absolute value? It's because (-x)^4=(-1)^4x^4=x^4.

We start by rewriting as

\sqrt[4]{\dfrac{2^23x^6y}{2^6x^4y^5}}

\sqrt[4]{\dfrac{2^23x^4x^2y}{2^42^2x^4y^4y}}

Since x\neq0, we have \dfrac xx=1, and the above reduces to

\sqrt[4]{\dfrac{3x^2y}{2^4y^4y}}

Then we pull out any 4th powers under the radical, and simplify everything we can:

\dfrac1{\sqrt[4]{2^4y^4}}\sqrt[4]{\dfrac{3x^2y}{y}}

\dfrac1{|2y|}\sqrt[4]{3x^2}

where y>0 allows us to write \dfrac yy=1, and this also means that |y|=y. So we end up with

\dfrac{\sqrt[4]{3x^2}}{2y}

making the last option the correct answer.

7 0
3 years ago
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