1. Given the following equation: N2 (g) + 3 H2 (g) ↔ 2NH3 (g) ΔH = -92 kJ/mol
a. this reaction is exothermic as ΔH is -ve
b. the equilibrium will shift 2 the left if nitrogen gas is removed
c. the equilibrium shift 2 the right if the temperature is lowered
d. the equilibrium shift 2 the left if ammonia (NH3) is added
e. principle of thermodynamic potential or Gibbs energy is used to answer B-D
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The volume of the nitrous oxide gas is 1729.3 Liters
<h3>What is the number of moles of gas present in 3.40 kg of nitrous oxide?</h3>
The number of moles of gas present in 3.40 kg of nitrous oxide is determined from the formula below:
Numbers of moles = mass/molar mass
the mass of nitrous oxide = 3.40 kg or 3400 g
the molar mass of nitrous oxide = 44.013 g/mol
Moles of gas = 3400 / 44.013
Moles of gas = 77.25 moles
Using the ideal gas equation to determine the volume of the gas:
PV= nRT
V = nRT/P
where;
- V is the volume of gas
- n is the number of moles of gas
- R is molar Gas constant = 0.082 L.atm/mol/K
- T is the temperature of the gas
V = 77.25 * 0.082 * 273 / 1
The volume of the gas = 1729.3 Liters
Learn more about ideal gas equation at: brainly.com/question/20212888
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Answer:
bleh
Explanation:
Neutralization reaction between magnesium hydroxide and hydrochloric acid Mg(OH)2(s) + 2HCl(aq) → 2H2O(l) + MgCl2(aq) b.
so uh pretty sure Mg(OH)2(s) + 2HCl(aq) → 2H2O(l) + MgCl2(aq) b.
correct me if im wrong <3
The name is sodium chloride. This is an ionic compound so you use the ionic naming system which is the name of the cation followed by the name of the anion. I hope this helps. Let me know if anything is unclear.
