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3 years ago

Which of the following statements describes the results of this reaction?

Chemistry

1 answer:

yanalaym [24]3 years ago

6 0

Answer: The correct answer is option (A).

Explanation:

Oxidation : A chemical reaction in which addition of oxygen occurs or removal of hydrogen occurs is called oxidation.

Reduction:A chemical reaction in which elimination of oxygen occurs or addition of hydrogen occurs is called reduction.

In a given reaction,:

$C_6H_{12}O_6+6O_2\rightarrow 6CO_2+6H_2O+Energy$

The glucose molecule is getting oxidized into carbon-dioxide. Before oxidation in glucose molecule ratio of carbon and oxygen atom was 1:1 which changes to 1:2 after oxidation of glucose into carbon-dioxide.

Hence, $C_6H_{12}O_6$ is getting oxidized.

The oxygen molecule is reduced because addition of hydrogen atoms are taking place in oxygen molecules which gives water after reduction.

Hence, $O_2$ is getting reduced.

So, correct answer is option (A).

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Answer:

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4 years ago

Some metal oxides, such as Sc2O3, do not react with pure water, but they do react when the solution becomes either acidic or bas

goldfiish [28.3K]

Answer:

$Sc_2O_3$ reacts with an acidic solution

Explanation:

Scandium Oxide $Sc_2O_3$ is a basic metal oxide which therefore reacts with acidic solution. An oxide is a compound that contains only two elements, one of which is oxygen .

The objective of this question is to Write a balanced chemical equation to support your answer.

The chemical equation to support the reaction of $Sc_2O_3$ with acidic solution is as follows:

Assuming the acidic solution to be HCl

$\mathbf{Sc_2O_3_{(s)} + 6 HCl_{(aq)} ----> 2 ScCl_{3(aq)} + 3H_2O_{(l)}}$

The ionic equation :

$\mathbf{Sc_2O_{3(s)} + 6H^+_{(aq)} ---> 2Sc^{3+}_{(aq)} + 3H_2O_{(l)}}$

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4 years ago

A 25.0 ml sample of an hcl solution is titrated with a 0.139 m naoh solution. the equivalence point is reached with 15.4 ml of b

Andreas93 [3]

the balanced equation for the acid base reaction is as follows

NaOH + HCl ---> NaCl + H₂O

stoichiometry of NaOH to HCl is 1:1

the number of NaOH moles is - 0.139 mol/L x 0.0154 L = 0.00214 mol

the number of NaOH moles reacted = number of HCl moles reacted

therefore number of HCl moles reacted = 0.00214 mol

volume of HCl containing 0.00214 mol - 25.0 mL

number of HCl moles in 25.0 mL - 0.00214 mol

therefore number of HCl moles in 1000 mL - 0.00214 mol / 25.0 mL x 1000 mL/L

molarity of HCl is 0.0856 mol/L

concentration of HCl is 0.0856 M

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