A 25.0 ml sample of an hcl solution is titrated with a 0.139 m naoh solution. the equivalence point is reached with 15.4 ml of b
2 answers:
You might be interested in
Answer : The mass of silver sulfadiazine produced can be, 71.35 grams.
Solution : Given,
Mass of = 25.0 g
Mass of = 50.0 g
Molar mass of = 231.7 g/mole
Molar mass of = 250.3 g/mole
Molar mass of = 357.1 g/mole
First we have to calculate the moles of and
.
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 mole of react with 1 mole of
So, 0.1998 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of
From the reaction, we conclude that
As, 2 mole of react with 2 mole of
So, 0.1998 mole of react with 0.1998 mole of
Now we have to calculate the mass of
Therefore, the mass of silver sulfadiazine produced can be, 71.35 grams.
Answer:
The answer is
<h2>19.31 g/cm³</h2>Explanation:
The density of a substance can be found by using the formula
From the question
mass of gold = 475.09g
volume = 24.6 cm³
The density of the gold is
We have the final answer as
<h3>19.31 g/cm³</h3>Hope this helps you