The fomula is NH4 (1+)
There are only two elements N and H.
As per oxidation state rules, the most electronegative element will have a negative oxidation state and the other element will have a positive oxidation state.
N is more electronative than H, so H will have a positive oxidation state and nitrogen will have a negative oxidation state.
You can also use the rule that states the hydrogen mostly has 1+ oxidation state,except when it is bonded to metals.
In conclusion the oxidation state of H in NH4 (1+) is 1+.
Now you must know that the sum of the oxidations states equals the charge of the ion, which in this case is 1+.
That implies that 4* (1+) + x = 1+
=> x = (1+) - 4(+) = 3-
Answer: the oxidation state of N is 3-, that is the option b.
Answer:
The required volume of hexane is 0.66245 Liters.
Explanation:
Volume of octane = v=1.0 L=![1000 cm^3](https://tex.z-dn.net/?f=1000%20cm%5E3)
Density of octane= d = ![0.703 g/cm^3](https://tex.z-dn.net/?f=0.703%20g%2Fcm%5E3)
Mass of octane ,m= ![d\times v=0.703 g/cm^3\times 1000 cm^3=703 g](https://tex.z-dn.net/?f=d%5Ctimes%20v%3D0.703%20g%2Fcm%5E3%5Ctimes%201000%20cm%5E3%3D703%20g)
Moles of octane =![\frac{m}{114 g/mol}=\frac{703 g}{114 g/mol}=6.166 mol](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7B114%20g%2Fmol%7D%3D%5Cfrac%7B703%20g%7D%7B114%20g%2Fmol%7D%3D6.166%20mol)
Mole percentage of Hexane = 45%
Mole percentage of octane = 100% - 45% = 55%
![55\%=\frac{6.166 mol}{\text{Total moles}}\times 100](https://tex.z-dn.net/?f=55%5C%25%3D%5Cfrac%7B6.166%20mol%7D%7B%5Ctext%7BTotal%20moles%7D%7D%5Ctimes%20100)
Total moles = 11.212 mol
Moles of hexane :
![45%=\frac{\text{moles of hexane }}{\text{Total moles}}\times 100](https://tex.z-dn.net/?f=45%25%3D%5Cfrac%7B%5Ctext%7Bmoles%20of%20hexane%20%7D%7D%7B%5Ctext%7BTotal%20moles%7D%7D%5Ctimes%20100)
Moles of hexane = 5.0454 mol
Mass of 5.0454 moles of hexane,M = 5.0454 mol × 86 g/mol=433.9044 g
Density of the hexane,D = ![0.655 g/cm^3](https://tex.z-dn.net/?f=0.655%20g%2Fcm%5E3)
Volume of hexane = V
![V=\frac{M}{D}=\frac{433.9044 g}{0.655 g/cm^3}=662.4494 cm^3\approx 0.66245 L](https://tex.z-dn.net/?f=V%3D%5Cfrac%7BM%7D%7BD%7D%3D%5Cfrac%7B433.9044%20g%7D%7B0.655%20g%2Fcm%5E3%7D%3D662.4494%20cm%5E3%5Capprox%200.66245%20L)
(1 cm^3= 0.001 L)
The required volume of hexane is 0.66245 Liters.
Answer:
586 kpa(kilopascal/1000 pascals)
Explanation:
given 1.24 atm(standard atmosphere), and 66.7 psi(pound force per square inch).
To find the total pressure we should use dalton's law of partial pressures which is the sum of the pressures of each individual gas.
then we convert them to pascals and divide by 1000 to get the measurement in kilopascal.
knowing that 1 atmosphere is proportional to around 14.696 psi. We can multiply our given measure of atm by that and sum it by psi like so. 1.24×14.6959 = 18.22298.
Then,
18.22298+ 66.7 = 84.92298
psi.
Since 1 psi is proportional to around 6894.76 pascals. 1 psi will be 68.9476 kilopascal. 84.92298 * 6.89476 = 585.523336 ≈ 586
Seven elements make up the compound