Answer:
3 choices :
-There's the largest possible number of mosquitoes when rainfall is about 2 cm.
- There are no mosquitoes when there is no rainfall
- There are no mosquitoes when rainfall is about 4 cm
Step-by-step explanation:
I took the quiz.
Difference is 0.8333333333
Let's use Pythagorean theorem.
![a^{2}+b^{2}=c^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%2Bb%5E%7B2%7D%3Dc%5E%7B2%7D)
where
![c](https://tex.z-dn.net/?f=c)
is the hypotenuse.
So if we set it up:
![7^{2}+b^{2}=13^{2}](https://tex.z-dn.net/?f=7%5E%7B2%7D%2Bb%5E%7B2%7D%3D13%5E%7B2%7D)
now we simplify:
![49+b^{2}=169](https://tex.z-dn.net/?f=49%2Bb%5E%7B2%7D%3D169)
and get
![b^{2}](https://tex.z-dn.net/?f=b%5E%7B2%7D)
by itself:
![b^{2}=120](https://tex.z-dn.net/?f=b%5E%7B2%7D%3D120)
Now to get
![b](https://tex.z-dn.net/?f=b)
by itself, we need to take the square root of both sides:
![b=\sqrt{120}](https://tex.z-dn.net/?f=b%3D%5Csqrt%7B120%7D)
And that's your answer!
3/4 + -5/8
---Find a common denominator
6/8 + -5/8
---Simplify
1/8
Hope this helps!
This can be displayed as a system of equations.
x = 3 + 5y
x - y = 11
Because we have a value of x we can plug it into the value of x in the second equation.
(3 + 5y) - y = 11
3 + 5y - y = 11
Combine like terms.
3 + 4y = 11
Subtract 3 from both sides.
4y = 8
Divide both sides by 4.
y = 2
Now that we have a constant value for y, we can replace the value of y in the second equation with 2 to solve for x.
x - 2 = 11
Add 2 to both sides.
x = 13
Now, let's verify.
13 = 3 + 5(2)
13 = 3 + 10
13 = 13 √ this is correct.
13 - 2 = 11
11 = 11 √ this is correct.
The first number, or x, is equal to 13.
The second number, or y, is equal to 2.