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Natalija [7]
2 years ago
6

A(n)=−5+6(n−1) What is the 12th term in the sequence

Mathematics
1 answer:
barxatty [35]2 years ago
4 0

Answer:

n/2[2a+(n-1)d]

12/2[2(-5)+(12-1)6]

66-10=56×6=336

336 is the 12th term

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Charlie has 324 magazines to pack in 5 boxes . He will pack the same number of magazines in each box. How many magazines will he
PtichkaEL [24]

Answer:

4 magazines left over

Step-by-step explanation:

\frac{324}{5} = 64 \frac{4}{5}

5 0
3 years ago
A survey finds customers are charged incorrectly for 44 out of every 10 items. Suppose a customer purchases 1414 items. Find the
seropon [69]

Answer:

The probability that the customer is charged incorrectly on at most 2 items is 3.979 × 10⁻².

Step-by-step explanation:

To solve the question, we note that we proceed with the binomial distribution formula as follows

Number of times the customer is incorrectly charged out of ever 10 items = 4

Therefore, the probability that the customer is incorrectly charged is 4/10 = 0.4

That is p(incorrect) = 0.4

Then the probability that the customer is charged incorrectly on at most 2 items is

P(x≤2) = P(x=0) + P(x=1) + P(x=2)

          = ₙC_r × p^r×q^{(n-r)} =

        P(x=0)   = ₁₄C₀ ×0.4⁰× 0.6¹⁴ =  7.836 × 10⁻⁴

        P(x=1)   =  ₁₄C₁ ×0.4¹× 0.6¹³ =  7.314 × 10⁻³

       P(x=2)  =   ₁₄C₂ ×0.4²× 0.6¹² =  3.169 × 10⁻²

∴ P(x≤2) = 7.836 × 10⁻⁴ + 7.314 × 10⁻³ + 3.169 × 10⁻² = 3.979 × 10⁻²

       P(x≤2) = 3.979 × 10⁻².

5 0
3 years ago
A car is 4m long. About how many cars would have to line up end to end to stretch from one town to another 23km away?
Bas_tet [7]
4 divided by 23 = 5 r1
4 0
3 years ago
Read 2 more answers
2. Tomás compró una bicicleta en $199.900. Primero, canceló la mitad y el resto en 7 cuotas de igual valor, con un interés total
Papessa [141]

Answer:

Cada cuota tendrá un valor de $14,850.

Step-by-step explanation:

Dado que Tomás canceló la mitad del valor de la bicicleta, la cual costaba $199.900, el valor pagado al inicio fue de $99,950 (199,900 / 2).

Luego, para el valor restante, Tomás suscribió a una financiación con un interés de $4,000, elevando el monto a pagar a $103,950, pagaderos en 7 cuotas. Por lo tanto, dichas cuotas tendrán cada una un valor de $14,850 (103,950 / 7).

4 0
3 years ago
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
3 years ago
Read 2 more answers
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