Answer:
<em>l = w + 3cm</em>
<em>l = w + 3cmp = 2l + 2w = 58cm</em>
<em>l = w + 3cmp = 2l + 2w = 58cm </em>
<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:</em>
<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58</em>
<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58</em>
<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13</em>
<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 </em>
<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:</em>
<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:l = (13cm) + 3cm = 16cm</em>
<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:l = (13cm) + 3cm = 16cmStep-by-step explanation:</em>
I hope this helps you.
Answer:
Enlargement Areas
Step-by-step explanation:
if you enlarge the little one, they will intersect each other perfectly because those triangles are similar and the same. they are just different sizes
hope this helps!
Answer:
x = 15
Step-by-step explanation:
We want to solve for x in 3*(2x + 5) = 3x + 4x
First simplify.
3*(2x + 5) = 7x
Next, distribute the 3.
3*2x + 3*5 = 7x
6x + 15 = 7x
15 = 7x - 6x
15 = x
It is 1 because if you divided 7over 7 it 1 so x=1
3/5*3
pretend that 3 has a denominator which is 1
3/5*3/1
mutiply the numerators together
3*3= 9
mutiply the denominators together
5*1= 5
Answer:
9/5, 1.8 and 1 4/5