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grin007 [14]
3 years ago
12

ex-formula"> X , Y and Z are the samples of water obtained from different sources. The types of salt dissolved in them are labelled in the picture. Now , Answer the following questions.
i. Identify the hardness of water that can be removed by boiling process.
ii. Which of them is soft water ?
iii. Write the chemical equation of the reaction that takes place when Z is treated with X , Y and Z.

~Random/Irrelevant answers will be reported!

Chemistry
2 answers:
nexus9112 [7]3 years ago
6 0
  • CaCO₃
  • MgCl₂
  1. Ca(HCO₃)+MgCl₂➙MgCO₃+CaCl₂+H₂O+CO₂
  2. 2CaCO₃+MgCl₂➙CaMg(CO₃)₂+CaCl₂
  3. Mg+Cl²➙MgCl₂

\\  \\  \\

Hope it helps:)

~ʆᵒŕ∂ཇꜱꜹⱽẻⱮë

Ilia_Sergeevich [38]3 years ago
5 0

Answer:

I .calcium carbonate

ii.Magnesium chloride

iii.CaCO3 + MgCl2 → CaCl2 + MgCO3

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Aliun [14]

Answer:

Chemical reaction, compound, molecule, covalent bonds, ionic bonds, ions. (first page)

Oxygen and hydrogen, 1 hydrogen 2 oxygen, H2O, a covalent bond, then mark off is always a liquid. (Second page)

Explanation:

6 0
3 years ago
2. (2 pts) How would you prepare 1.5 liters of 2 M KCI (MW=74.55 g/mol)
ra1l [238]

Answer:

Dissolve 226 g of KCl in enough water to make 1.5 L of solution

Explanation:

1. Calculate the moles of KCl needed

n = \text{1.5 L} \times \dfrac{\text{2 mol}}{\text{1 L}}= \text{3.0 mol}

2. Calculate the mass of KCl

m = \text{3.0 mol} \times \dfrac{\text{74.55 g}}{\text{1 mol}}= \text{224 g}

3. Prepare the solution

  • Measure out 224 g of KCl.
  • Dissolve the KCl in a few hundred millilitres of distilled water.
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8 0
3 years ago
Select correct examples of linear molecules for five electron groups. Select correct examples of linear molecules for five elect
Shalnov [3]

Explanation:

Formula to calculate hybridization is as follows.

                Hybridization = \frac{1}{2}[V+N-C+A]

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

So, hybridization of BeCl_{2} is as follows.

              Hybridization = \frac{1}{2}[V + N - C + A]

                                    = \frac{1}{2}[2 + 2]

                                    = 2

Hybridization of BeCl_{2} is sp. Therefore, BeCl_{2} is a linear molecule. There will be only two electron groups through which Be is attached.

Similarly, hybridization of XeF_{2} is calculated as follows.

         Hybridization = \frac{1}{2}[V + N - C + A]

                                    = \frac{1}{2}[8 + 2]

                                    = 5

Therefore, hybridization of XeF_{2} is sp^{3}d. Therefore, [tex]XeF_{2} is also a linear molecule. Though there are three lone pair of electrons present on a xenon atom and it is further attached with fluorine atoms through two electron pairs. Hence, there are in total five electron groups.

Thus, we can conclude that out of the given options XeF_{2} is the correct examples of linear molecules for five electron groups.

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Aleks04 [339]

Answer:

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Natalka [10]

Answer:

The groupings of elements in the periodic table reveal various trends, present in groups such as the alkali metals and noble gases, or the lanthanides and actinides. The periodic table can be used to find information on elements or predict the properties of as-of-yet undiscovered elements.

Explanation:

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