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morpeh [17]
3 years ago
7

Which situation has a probability of 1/2 I will give 5 star

Mathematics
2 answers:
Alexeev081 [22]3 years ago
7 0

Answer:

A coinflip

Step-by-step explanation:

And having two buttons that look the same and having one do something, and one do something different, and you having to choose one of those buttons, but you are not sure of what neither one of those do.

For example, a button turns on the lights, and the other turns on the air conditioner :O

But for some reason they both look the same in every aspect and you would need to choose one also for some reason

Hmm

Dennis_Churaev [7]3 years ago
4 0

Answer:

A coin flip

Step-by-step explanation:

:)

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What’s the answer to 3\4(8x + 12) = 3
Artemon [7]

Answer:

x = - 1

Step-by-step explanation:

\frac{3}{4} (8x + 12) = 3 ( multiply both sides by 4 to clear the fraction )

3(8x + 12) = 12 ( divide both sides by 3 )

8x + 12 = 4 ( subtract 12 from both sides )

8x = - 8 ( divide both sides by 8 )

x = - 1

4 0
2 years ago
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Find the slope of the line that passes through (3,0) and (-10,-6)
balandron [24]

Answer:

Slope: 6/13

Step-by-step explanation:

7 0
3 years ago
6+3(x+4)=24. solve the following equation please ​
Evgen [1.6K]

Answer:

The answer to this equation will be 2 for x

Step-by-step explanation:

Hope this Helped

6 0
3 years ago
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A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions
faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3><u>Solution:</u></h3>

Given that  

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

<em><u>The area of rectangle is given as:</u></em>

\text {Area of rectangle }=length \times width

Area of rectangular parking lot = length of rectangular parking plot \times width of the rectangular parking

\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}

But it is given that Area of rectangular parking lot = 15000 square feet

\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}

Solving the above quadratic equation using quadratic formula

<em><u>General form of quadratic equation is  </u></em>

{ax^{2}+\mathrm{b} x+\mathrm{c}=0

And quadratic formula for getting roots of quadratic equation is

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}

\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet  

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0
3 years ago
(2a 2 + a + 3) (a - 1) Please help
ArbitrLikvidat [17]
Hey there!

You can use distributive property, as I mentioned in your previous questions.

multiply...
2a² × a = 2a³
2a² × -1 = -2a²
a × a = a²
a × -1 = -a
3 × a = 3a
3 × -1 = -3

add all those terms..
2a³ - 2a² + a² - a + 3a - 3
add the like terms

2a³ - a² + 2a - 3

Hope this helped :)
4 0
3 years ago
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