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goldenfox [79]
3 years ago
5

A bag contains 9 marbles: 4 are green, 2 are red, and 3 are blue Yoko chooses a marble at random, and without putting it back, c

hooses another one at
random. What is the probability that the first marble is red and the second is blue? Write your answer as a fraction in simplest form.
Mathematics
1 answer:
Virty [35]3 years ago
5 0

Answer:

1/12

Step-by-step explanation:

Probability of first marble being red is 2/9.

Then since he is not replacing the marble, there is only 8 marbles left in the bag. So the probability of choosing blue is 3/8. Then you multiply 2/9 × 3/8 = 6/72.

In simplest form: 1/12

You might be interested in
consider the function and then use calculus to answer the questions that follow 1 1/x 5/x^2 1/x^3 (a) Find the interval(s) where
boyakko [2]

Answer:

a)X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

b)Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

Step-by-step explanation:

From the question we are told that

The Function

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

Generally the differentiation of function f(x) is mathematically solved as

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

f(x)=\frac{x^3+x^2+5x+1}{x^2}

Therefore

f'(x)=\frac{x^2+10x+3}{x^4}

Generally critical point is given as

f'(x)=0

\frac{x^2+10x+3}{x^4}=0

x=-5 \pm\sqrt{22}

Generally the maximum and minimum x value for critical point is mathematically solved as

f'(-5 \pm\sqrt{22})

Where

Maximum value of x

f'(-5 +\sqrt{22})

Minimum value of x

f'(-5 +\sqrt{22})

Therefore interval of increase is mathematically given by

f'(-5 -\sqrt{22}),f'(-5 +\sqrt{22})

f(x)

Therefore interval of decrease is mathematically given by

(-\infty,-5 -\sqrt{22}),f'(-5 +\sqrt{22},0),(0,\infty)

Generally the second differentiation of function f(x) is mathematically solved as

f''(x)=\frac{2(x^2+15x+6)}{x^5}

Generally the point of inflection is mathematically solved as

f''(x)=0

x^2+15x+6=0

Therefore inflection points is given as

x=\frac{1}{2} (-15 \pm \sqrt{201}

f''(x)>0,\frac{1}{2}(-15-\sqrt{201})

a)Generally the concave upward interval X is mathematically given as

X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

f''(x)

b)Generally the concave downward interval Y is mathematically given as

Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

5 0
2 years ago
Help will mark Brainliest!!​
BartSMP [9]

Answer:

-20.5

Step-by-step explanation:

Using a basic calculator, you divide 10.25 by -.5 which easily gives -20.5

5 0
2 years ago
ASAP HELP! BRAINLIEST! can someone help me with this? i need work shown. will mark brainliest!
ki77a [65]

Answer:

  4x^2 +12x +44 remainder 161x +84

Step-by-step explanation:

At each step, the quotient term is the ratio of the leading dividend term to the leading divisor term. The first quotient term, for example, is ...

  (4x^4)/(x^2) = 4x^2

The quotient term found this way is multiplied by the divisor and subtracted from the dividend. The difference is the new dividend and the process repeats.

You're done when the degree of the dividend is less than the degree of the divisor. This remainder can be expressed as a fraction with the divisor as the denominator.

  \dfrac{4x^4+5x-4}{x^2-3x-2}=4x^2+12x+44+\dfrac{161x+84}{x^2-3x-2}

5 0
2 years ago
How do I solve x(3x-17)=0 using the square root property
scZoUnD [109]

Answer:

x = 0 or x = \frac{17}{3}

Step-by-step explanation:

We have the quadratic equation of variable x and we have to solve the equation using the square root property.

Now, we have x(3x - 17) = 0

⇒ 3x² - 17x = 0

⇒ 3(x^{2}  - \frac{17}{3}x ) = 0

⇒ x^{2} - 2 \times (\frac{17}{6}) \times x + (\frac{17}{6} )^{2} = (\frac{17}{6} )^{2}

⇒ (x - \frac{17}{6})^{2} = (\frac{17}{6} )^{2}

Now,square rooting both sides we get,  

x - \frac{17}{6} = \pm\frac{17}{6}

Therefore, either x = 0 or x = \frac{17}{3} (Answer)

8 0
3 years ago
NAMED BRAINLIEST FOR FIRST ANSWERER!!
TiliK225 [7]

Answer:

$44 hope it helps

Step-by-step explanation:

3 0
3 years ago
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