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babunello [35]
3 years ago
11

Solve for x: |1/3-x/4|=7/12

Mathematics
1 answer:
ozzi3 years ago
4 0

Your answer is x={-1, 11/3}

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What is 2/5 plus 1/3
leva [86]
First, you need to get the denominators (the bottom number) the same.  The smallest number to get them to is 15.

So, what you need to do is take 2/5 and multiply the bottom by 3 to get 15, and since you did it to the bottom, you need to do it to the top too.   So you would get, 6/15.

Then, for 1/3, take the bottom number and multiply it by 5.  Then, since you did it to the bottom, do it to the top as well.  You would get 5/15.

Then, you need to put them side by side.  You don't add the bottom, so your denominator would remain 15, but your numerator (top) would get added.

<u> 6</u> + <u>5</u>     =   <u>11</u> 
15  15         15
6 0
3 years ago
Evaluate the principal square root of 64
anygoal [31]
The square root of 64 is 8 because 8x8 is 64
3 0
2 years ago
Read 2 more answers
Determine formula of the nth term 2, 6, 12 20 30,42​
nalin [4]

Check the forward differences of the sequence.

If \{a_n\} = \{2,6,12,20,30,42,\ldots\}, then let \{b_n\} be the sequence of first-order differences of \{a_n\}. That is, for n ≥ 1,

b_n = a_{n+1} - a_n

so that \{b_n\} = \{4, 6, 8, 10, 12, \ldots\}.

Let \{c_n\} be the sequence of differences of \{b_n\},

c_n = b_{n+1} - b_n

and we see that this is a constant sequence, \{c_n\} = \{2, 2, 2, 2, \ldots\}. In other words, \{b_n\} is an arithmetic sequence with common difference between terms of 2. That is,

2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2

and we can solve for b_n in terms of b_1=4:

b_{n+1} = b_n + 2

b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2

b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2

and so on down to

b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)

We solve for a_n in the same way.

2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)

Then

a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)

a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))

a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))

and so on down to

a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2

\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}

6 0
2 years ago
What slope of the points (9,7) and (3,3)
Ymorist [56]

Answer:

6/4

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the square route of 5?
denis-greek [22]

Square root are the same 2 numbers multiplied.

Ex: 8*8=64 (Square root is 8)

9*9=81 (Square root is 9)

2.2360679775*2.2360679775=5

Answer=2.2360679775


6 0
2 years ago
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