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Zielflug [23.3K]
2 years ago
12

The base of a solid right pyramid is a square with an

Mathematics
1 answer:
zhuklara [117]2 years ago
6 0

Answer:

Volume = ⅓n²(n-1) or ⅓(n³ - n²)

Step-by-step explanation:

Given

Solid Shape: Right pyramid

Edge= n units

Height= n - 1 units

Required

Volume of the pyramid

The volume of a right pyramid is

Volume = ⅓Ah

Where A represents the area of the base

h represent the height of the pyramid

Since it has a square base;

The area is calculated as follows

Area, A = edge * edge

A = n * n

A = n²

Recall that

Volume = ⅓Ah

Substitute n² for A and n - 1 for h

The expression becomes

Volume = ⅓ * n² * (n - 1)

Volume = ⅓n²(n-1)

The expression can be solved further by opening the bracket

Volume = ⅓(n³ - n²)

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A music club has 35 drum players. If 25% of the total number of members in the club are drum players, what is the total number o
Pachacha [2.7K]

Answer:

140

Step-by-step explanation:

Since 25% is 1/4 of 100, that means that 35 is 1/4 of the total amount of members in the club. So, 35 times 4 is 140.

3 0
3 years ago
Which of the following is the weight of the cargo in a truck if 1/3 of the weight is 516 Ibs?
Anni [7]

Answer:

1548 lb

Step-by-step explanation:

Let the truck's weight be w.

Then (1/3)w = 516 lb

Solve for the truck's weight by multiplying both sides of this equation by 3:

w = 1548 lb (Answer B)

8 0
3 years ago
3x-9=3(x-3) how many solutions​
Colt1911 [192]

Answer:

All Real Numbers

Step-by-step explanation:

Step 1:

3x - 9 = 3 ( x - 3 )        Equation

Step 2:

3x - 9 = 3x - 9       Multiply

Step 3:

- 9 = - 9       Subtract 3x on both sides

Answer:

All Real Numbers

Hope This Helps :)

4 0
2 years ago
PLZ HELP WILL RATE BRAINLIEST REMEMBER IT HAS 5 DIGITS
kobusy [5.1K]

Answer:

i figured it out the number is 12,316 if i am correct

7 0
3 years ago
Read 2 more answers
The sum of four consecutive integers is at least 18. What's the smallest consecutive integer to make this statement true?
Ghella [55]

Let the four consecutive integers be

x , x+1, x+2, x+3

ATQ, Their sum is 18

\sf \: x + x + 1 + x + 2 + x + 3 = 18

\sf \: 4x + 1 + 2 + 3 = 18

\sf4x + 6 = 18

\sf4x = 18 - 6

\sf4x = 12

\boxed{ \mathfrak{x = 3}}

<h3>Now,</h3>

  • 1st number = x = 3
  • 2nd number = x+1 = 3+1 = 4
  • 3rd number = x+2 = 3+2 = 5
  • 4th number = x+3 = 3+3 = 6

<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>

6 0
2 years ago
Read 2 more answers
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