Solution :
We have to prove that
(De-Morgan's law)
Let
then
and 
and so
and
.
Thus,
and so 
Hence,
.........(1)
Now we will show that 
Let
⇒
Thus x is present neither in the set A nor in the set B, so by definition of the union of the sets, by definition of the complement.
and 
Therefore,
and we have
.............(2)
From (1) and (2),
Hence proved.
Answer:
I think it's diagonal....
Answer: do 2.1 times 100 than that answer times 0.6
Step-by-step explanation:
Answer:
i can't do that I don't know how I'm sorry