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Gala2k [10]
3 years ago
14

Campare and Conteast Physical and chemical properties.

Chemistry
1 answer:
I am Lyosha [343]3 years ago
3 0

Answer:

Physical properties are changes in color, weight, mass, density, volume, whether it is freezing, tarnishing, boiling, etc. while chemical properties are changes in the compound of the object such as whether an object is/isn't flammable, affected by acid, it dissolves, ferments, rots, ignites in water, etc.

Explanation:

Physical property examples: a piece of steel is cut in half, a sugar cube is ground up into a powder, ice melts into water, clouds form in the sky, you mow the lawn, the water turned purple when you dropped red and blue dye in it, leaves grow in the spring, ethyl alcohol boils at 79° C, you cut apples up

Chemical property examples: pancakes cook on the griddle, fireworks explode in th sky, Alka-Seltzer gives off carbon dioxide when added to water, roasting a marshmellow, milk sours when left on the counter, burning wood in a bonfire, salt dissolves in water, food is digested in the stomach

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Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4
inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

M=\frac{n_{solute}}{V_{solution}}

So you can solve for the moles of the solute:

n_{solute}=M*V_{solution}

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

n_{solute}=1mol/L*1.5L=1.5mol

But this is just a supposition.

Regards.

4 0
3 years ago
What experiment did J.J thomson do?
Fittoniya [83]

Answer: C

Explanation:

7 0
3 years ago
Read 2 more answers
6. If 4 mole of the rocket fuel ammonium perchlorate, NH4C/04 (s) is
Bond [772]

Answer:

144g of H₂O

Explanation:

3NH₄ClO₄(s) + 3Al → Al₂O₃(s) + AlCl₃(s) + 3NO(g) + 6H₂O(g)

From the equation:

3 moles of NH₄ClO₄ produced 6 moles of H₂O

4 moles of NH₄ClO₄ produced ? moles of H₂O

(4 ₓ 6)/3 = \frac{24}{3} = 8 moles of H₂O

1 mole of H₂O = (1 × 2) + 16 = 18g (The Relative Molecular mass of H₂O)

8 moles of H₂O = ?

Therefore 8 × 18 = 144g

=144g of H₂O

3 0
2 years ago
How many grams of HNO3 are produced when 59.0 g of NO2 completely reacts?
Anettt [7]

Answer:

53.7 grams of HNO3 will be produced

Explanation:

Step 1: Data given

Mass of NO2 = 59.0 grams

Molar mass NO2 = 46.0 g/mol

Step 2: The balanced equation

3NO2 + H2O→ 2HNO3 + NO

Step 3: Calculate moles NO2

Moles NO2 = 59.0 grams / 46.0 g/mol

Moles NO2 = 1.28 moles

Step 4: Calculate moles HNO3

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

For 1.28 moles NO2 we'll have 2/3 * 1.28 =0.853 moles HNO3

Step 7: Calculate mass HNO3

Mass HNO3 = 0.853 moles * 63.01 g/mol

Mass HNO3 = 53.7 grams

53.7 grams of HNO3 will be produced

3 0
3 years ago
How many protons, neutrons, and electrons are in Ca-44?
Mariulka [41]
Protons = 20
Electron = 20
Neutrons = 20
Hope this Helps :)
4 0
3 years ago
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