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3 years ago

7

How does a allergy develop? PLEASE HELP!

2 answers:

mars1129 [50]3 years ago

7 0

Answer: im not fully sure but from what i rememeber Allergies develop when your immune system mistakenly identifies a thing such as pollen, mold or food as harmful then your body reacts to it

Explanation:

Nikolay [14]3 years ago

4 0

Allergies arise when a foreign material such as pollen, bee venom or pet dander responds to your immune system or a food that in most people does not cause a reaction. Substances known as antibodies are formed by your immune system.

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The function of the heat exchanger in a nuclear reactor is to...

Ganezh [65]

Answer:

cool the tractor water system

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2 years ago

Please help fasts thanks

Charra [1.4K]

Answer:

amplitude

Explanation:

The amplitude of a wave is the distance from the centre line (or the still position) to the top of a crest or to the bottom of a trough

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3 years ago

Read 2 more answers

What volume (in L) of oxygen will be required to produce 77.4 L of water vapor in the reaction below?

Inga [223]

Answer:

90.3 L

Explanation:

Given data:

Volume of water produced = 77.4 L

Volume of oxygen required = ?

Solution:

Chemical equation:

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

It is known that,

1 mole = 22.414 L

There are 7 moles of oxygen = 7×22.414 = 156.9 L

There are 6 moles of water = 6×22.414 = 134.5 L

Now we will compare:

H₂O : O₂

134.5 : 156.9

77.4 : 156.9/134.5×77.4 =90.3 L

So for the production of 77.4 L water 90.3 L oxygen is required.

8 0

3 years ago

A gas occupies 200ml at a temperature of 26 degrees Celsius and 76mmHg pressure. Find the volume at -3degree Celsius with the pr

sergey [27]

Answer:

184.62 ml

Explanation:

Let $p_1, v_1,$ and $T_1$ be the initial and $p_2, v_2,$ and $T_2$ be the final pressure, volume, and temperature of the gas respectively.

Given that the pressure remains constant, so

$p_1=p_2$ ...(i)

$v_1$ = 200 ml

$T_1= 26 ^{\circ}C = 273+26 =299$ K

$T_2= 3 ^{\circ}C = 273+3 =276$ K

From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

$p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)$

For the final condition,

$p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)$

Equating equation (i), and (ii)

$\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}$

$\frac{v_1}{T_1}=\frac{v_2}{T_2}$ [from equation (i)]

$v_2=\frac{T_2}{T_1} \times v_1$

Putting all the given values, we have

$v_2=\frac{276}{299} \times 200 = 184.62 \; ml$

Hence, the volume of the gas at 3 degrees Celsius is 184.62 ml.

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3 years ago

What does a balanced equation allows you to determine

Allushta [10]

It allows you to determine the relation between the reactants and the products.

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3 years ago