The mass of oxygen is 236.4 g.
Explanation:
To find the mass of oxygen in 325 g of carbon dioxide (CO₂) we follow the next algorithm.
First we calculate the molar weight of carbon dioxide:
molar weight of CO₂ = molar weight of carbon × 1 + molar weight of oxygen × 2
molar weight of CO₂ = 12 × 1 + 16 × 2 = 44 g/mole
Now we devise the following reasoning:
if in 44 g of CO₂ there are 32 g of oxygen
then in 325 g of CO₂ there are X g of oxygen
X = (32 × 325) / 44 = 236.4 g oxygen
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molar weight
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Answer:
2 N2O5 4 NO2 + 1 O2
Explanation:
For the last one you dont really have to add the 1 but you can if its nedded,
since 3 divided by 3 is 1.
Answer:

Explanation:
= Initial concentration = 1.28 M
= Final concentration = ![0.17[A]_0](https://tex.z-dn.net/?f=0.17%5BA%5D_0)
k = Rate constant = 0.0632 s
t = Time taken
For first order reaction we have the relation
![kt=\ln\dfrac{[A]_0}{[A]}\\\Rightarrow t=\dfrac{\ln\dfrac{[A]_0}{[A]}}{k}\\\Rightarrow t=\dfrac{\ln\dfrac{[A]_0}{0.17[A]_0}}{0.0632}\\\Rightarrow t=28.037\ \text{s}](https://tex.z-dn.net/?f=kt%3D%5Cln%5Cdfrac%7B%5BA%5D_0%7D%7B%5BA%5D%7D%5C%5C%5CRightarrow%20t%3D%5Cdfrac%7B%5Cln%5Cdfrac%7B%5BA%5D_0%7D%7B%5BA%5D%7D%7D%7Bk%7D%5C%5C%5CRightarrow%20t%3D%5Cdfrac%7B%5Cln%5Cdfrac%7B%5BA%5D_0%7D%7B0.17%5BA%5D_0%7D%7D%7B0.0632%7D%5C%5C%5CRightarrow%20t%3D28.037%5C%20%5Ctext%7Bs%7D)
Time taken to reach the required concentration would be
.
Answer:
The valence shell has higher energy than other occupied shells
Explanation:
According to Bohr's model of the atom, he suggested that the extranuclear part consists of electrons in specific spherical orbits around the nucleus.
His model suggests that the electron can move round the nucleus in certain permissible orbits or energy levels. The ground state is the lowest energy state available to the electron. The excited state is any level higher than the ground state.
The valence electrons are in the outermost shell of an atom. These electrons are of the highest energy levels in the atom
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The correct answer is 0.44ml
For information, promethazine is a neuroleptic antihistamine inhibitor of H1 receptors of the phenothiazine family. It is a medicine used in the treatment of allergy (like rhinitis) and transient insomnia.
To respond to this exercise, it is necessary to cross-multiply.
In the antihistamine bottle solution:
25 mg corresponds to 1 ml
11 mg corresponds to: 11/25 = 0.44 ml of the solution.
This 0.44ml is taken from the bottle and put to the syringe.