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eduard
2 years ago
8

A recent study of the hourly wages of maintenance crew members for major airlines showed that the mean hourly salary was $20.50,

with a standard deviation of $3.50. assume the distribution of hourly wages follows the normal probability distribution. we select a crew member at random. what is the probability the crew member earns
Mathematics
1 answer:
RSB [31]2 years ago
8 0
You ended without giving the values, so we can't get the exact answer. However, I can tell you steps.

First, you need to find the z-score. Then, look up the z-score on a normal distribution table and you will get the percent.

Let's call your value X. Just plug X into the equation below and you will have your z-score.

(x - 20.5) / 3.5 = z

Now, look up the z-score and you will have your probability.<span />
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olganol [36]
The answer is: A because
3 0
3 years ago
Read 2 more answers
At the movie theater, childs admission is $6.10. Adult admission is $9.40. On Tuesday four times as many adult tickets as child
Harlamova29_29 [7]

Answer:

The number of children's tickets sold was 27

Step-by-step explanation:

Let

x ----> the number of children's tickets sold

y ----> the number of adult's tickets sold

we know that

6.10x+9.40y=1,179.90 ----> equation A

y=4x ----> equation B

Solve the system by substitution

Substitute equation B in equation A

6.10x+9.40(4x)=1,179.90

solve for x

6.10x+37.6x=1,179.90

43.7x=1,179.90

x=27

therefore

The number of children's tickets sold was 27

8 0
3 years ago
Which of the following ordered pairs are y-intercepts? Check all that apply
Varvara68 [4.7K]

A y-intercept is the value at which x = 0.

(4,0) is not a y-intercept because x = 4.

(-1, 1) is not a y-intercept because x = -1.

(0,0) is a y-intercept because x = 0.

(0, -7) is a y-intercept because x = 0.

(-2, 2) is not a y-intercept because x = -2.

(0, -0.25 is a y-intercept because x = 0.

8 0
3 years ago
Read 2 more answers
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of days an
solniwko [45]

Answer:

(a) 283 days

(b) 248 days

Step-by-step explanation:

The complete question is:

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. ​(a) What is the minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths? ​(b) What is the maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths?

Solution:

The random variable <em>X</em> can be defined as the pregnancy length in days.

Then, from the provided information X\sim N(\mu=268, \sigma^{2}=12^{2}).

(a)

The minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths implies that:

P (X > x) = 0.11

⇒ P (Z > z) = 0.11

⇒ <em>z</em> = 1.23

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\\\1.23=\frac{x-268}{12}\\\\x=268+(12\times 1.23)\\\\x=282.76\\\\x\approx 283

Thus, the minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths is 283 days.

(b)

The maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths implies that:

P (X < x) = 0.05

⇒ P (Z < z) = 0.05

⇒ <em>z</em> = -1.645

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\\\-1.645=\frac{x-268}{12}\\\\x=268-(12\times 1.645)\\\\x=248.26\\\\x\approx 248

Thus, the maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths is 248 days.

8 0
2 years ago
Solve the following quadratic equation for all values of xx in simplest form.<br> 4(x-2)^2=16
kvv77 [185]

Answer:

x=4, x=0

Step-by-step explanation:

I answered this here, lol.

brainly.com/question/23072490

8 0
2 years ago
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