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GalinKa [24]
3 years ago
5

Solve for 0: sin0=cos(0+25)​

Mathematics
1 answer:
leonid [27]3 years ago
8 0

Answer:

0= 0.991203

And its a false solution

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Ms. Williams wanted information about how well her students were
Arturiano [62]

Answer:

https://www.pittsfordschools.org/cms/lib/NY02205365/Centricity/Domain/683/ANSWER%20KEY%20TO%20ALL%20HOMEWORK.pdf

Step-by-step explanation:

If this doesn’t work I’m sorry but that’s the link!

5 0
3 years ago
You subscribe to m different magazines.Your friend subscribed to 2 fewer than you.
lozanna [386]

The expression would be m-2

3 0
3 years ago
Where would fraction<br> 22/11 belong on a #6 number line
pickupchik [31]
22/11 is equal to 2
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6 0
3 years ago
A parabola has a focus of F(2, -0.5) and a directrix of y=-1.5 P(x,y) represents any point on the parabola, while D(x, -1.5) rep
prohojiy [21]
The sketch of the parabola is attached below

We have the focus (a,b) = (2, -0.5)
The point P(x,y)
The directrix, c at y=-1.5

The steps to find the equation of the parabola are as follows

Step 1
Find the distance between the focus and the point P using Pythagoras. We have two coordinates; (2, -0.5) and (x,y).
We need the vertical and horizontal distances to find the hypotenuse (the diagram is shown in the second diagram).
The distance between the focus and point P is given by
\sqrt{ (x-a)^{2}+ (y-b)^{2} }

Step 2
Find the distance between the point P to the directrix c. It is a vertical distance between y and c, expressed as y-c

Step 3
The equation of parabola is then given as 
\sqrt{ (x-a)^{2}+ (y-b)^{2} }=y-c
(x-a)^{2}+ (y-b)^{2}= (y-c)^{2} ⇒ substituting a, b and c
(x-2)^{2}+ (y--0.5)^{2}  = (y--1.5)^{2}
(x-2)^{2}+ (y+0.5)^{2}= (y+1.5)^{2}⇒Rearranging and making y the subject gives

y= \frac{ x^{2} }{2} -2x+1

7 0
4 years ago
Evaluate the numerical expression 24×5-41
Alinara [238K]
Start by multiplying 24*5 (PEMDAS)
24*5= 125
125-41=84
3 0
3 years ago
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