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Marat540 [252]
3 years ago
11

Find the area of right triangle. If necessary, round to the nearest tenth.

Mathematics
1 answer:
Finger [1]3 years ago
5 0

Answer:

b. 24 yd

Step-by-step explanation:

Hi, since we have a  right triangle we have to apply the Pythagorean Theorem:, to find the missing side.

c^2 = a^2 + b^2

Where c is the hypotenuse of the triangle (10 yd) and a and b are the other sides.

Replacing with the values given:

10^2 = 6^2 + b^2

100 = 36+b^2

100-36 = b^2

64 = b^2

√64 = b

b= 8

Now, we can calculate the area:

A =1/2x base x height = 1/2 x 8 x 6 = 24 yd

Feel free to ask for more if needed or if you did not understand something.

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Sampson solves the inequality as shown below.
astraxan [27]

Answer:

subtract 3 from both sides

Step-by-step explanation:

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Pretend that you are a strawberry farmer and the market price of strawberries went up $1 per pound to $4 per pound. Explain what
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Increase the price of the strawberries to keep the same profit
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Find the missing lengths of the sides
Ket [755]

ANSWER

The correct answer is C

EXPLANATION

The given triangle is a right triangle. Since two angles are equal, it is a right isosceles triangle.

This implies that, x=8 units.

Using Pythagoras Theorem,

{y}^{2}  =  {8}^{2}  +  {8}^{2}

This implies that:

{y}^{2}  = 64  +  64

{y}^{2}  =128

Take positive square root,

{y}  =  \sqrt{128}

{y}  = 8 \sqrt{2}

The correct answer is C

5 0
3 years ago
Read 2 more answers
2.<br> What is the next term of the arithmetic sequence 6, 10, 14, 18, ...?
riadik2000 [5.3K]

Answer:

22

Step-by-step explanation:

In this sequence, the next number is found by adding 4.

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Test scores of the student in a school are normally distributed mean 85 standard deviation 3 points. What's the probability that
Mrrafil [7]

Answer:

The probability that a random selected student score is greater than 76 is \\ P(x>76) = 0.99865.

Step-by-step explanation:

The Normally distributed data are described by the normal distribution. This distribution is determined by two <em>parameters</em>, the <em>population mean</em> \\ \mu and the <em>population standard deviation</em> \\ \sigma.

To determine probabilities for the normal distribution, we can use <em>the standard normal distribution</em>, whose parameters' values are \\ \mu = 0 and \\ \sigma = 1. However, we need to "transform" the raw score, in this case <em>x</em> = 76, to a z-score. To achieve this we use the next formula:

\\ z = \frac{x - \mu}{\sigma} [1]

And for the latter, we have all the required information to obtain <em>z</em>. With this, we obtain a value that represent the distance from the population mean in standard deviations units.

<h3>The probability that a randomly selected student score is greater than 76</h3>

To obtain this probability, we can proceed as follows:

First: obtain the z-score for the raw score x = 76.

We know that:

\\ \mu = 85

\\ \sigma = 3

\\ x = 76

From equation [1], we have:

\\ z = \frac{76 - 85}{3}

Then

\\ z = \frac{-9}{3}

\\ z = -3

Second: Interpretation of the previous result.

In this case, the value is <em>three</em> (3) <em>standard deviations</em> <em>below</em> the population mean. In other words, the standard value for x = 76 is z = -3. So, we need to find P(x>76) or P(x>-3).

With this value of \\ z = -3, we can obtain this probability consulting <em>the cumulative standard normal distribution, </em>available in any Statistics book or on the internet.

Third: Determination of the probability P(x>76) or P(x>-3).

Most of the time, the values for the <em>cumulative standard normal distribution</em> are for positive values of z. Fortunately, since the normal distributions are <em>symmetrical</em>, we can find the probability of a negative z having into account that (for this case):

\\ P(z>-3) = 1 - P(z>3) = P(z

Then

Consulting a <em>cumulative standard normal table</em>, we have that the cumulative probability for a value below than three (3) standard deviations is:

\\ P(z

Thus, "the probability that a random selected student score is greater than 76" for this case (that is, \\ \mu = 85 and \\ \sigma = 3) is \\ P(x>76) = P(z>-3) = P(z.

As a conclusion, more than 99.865% of the values of this distribution are above (greater than) x = 76.

<em>We can see below a graph showing this probability.</em>

As a complement note, we can also say that:

\\ P(z3)

\\ P(z3)

Which is the case for the probability below z = -3 [P(z<-3)], a very low probability (and a very small area at the left of the distribution).

5 0
3 years ago
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