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Solnce55 [7]
3 years ago
7

2 x (-8) X (-7) 1-5) =​

Mathematics
1 answer:
abruzzese [7]3 years ago
7 0

Answer:

108

Step-by-step explanation:

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A Demolition ball weigths 2 tons . what is the weigtht in ounces?also what is a demolition ball?
kkurt [141]

Answer:

  64,000 oz

Step-by-step explanation:

A demolition (wrecking) ball is a relatively large dense mass, often spherical, typically swung from a crane, used to demolish buildings or other structures.

We assume you want to convert from a US short ton (2000 pounds) to Avoirdupois ounces (16 ounces per pound).

Then your ball's weight is ...

  (2 tons)(2000 lb/ton)(16 oz/lb) = 64,000 oz

3 0
3 years ago
Here is a list of test scores: 86, 90, 93, 85, 79, 92 Find the mean ( average) of the test scores.
Mrac [35]
Add them all up: 86+90+93+85+79+92=525
divide by 6 (because they provide 6 percentages): 525/6
mean=87.5
5 0
3 years ago
Read 2 more answers
Find the slope of the line that passes through each pair of points (8,2) (8, -1)
mash [69]

Answer:

Undefined

Step-by-step explanation:

Use the following formula to solve for slope:

\frac{y_2-y_1}{x_2-x_1} =m

m=\frac{(-1)-2}{8-8}

m=\frac{-3}{0}

The equation is not a function and therefore the slope is undefined because there are multiple y values for a single x value.

5 0
3 years ago
How do you say 1.75 in words
gizmo_the_mogwai [7]
You would say one and seventy-five hundredths
5 0
3 years ago
Read 2 more answers
ATCs are required to undergo periodic random drug testing.
aleksandr82 [10.1K]

Answer:

The responsess to the given question can be defined as follows:

Step-by-step explanation:

P(medication\ used) = 0.007 \\\\P( drug \not\ used ) = 1 - 0.007 = 0.993\\\\P(test\ positive  | medication \ used) = 0.96 \\\\ P(test \ negative | medication \ used) = 1 - 0.96 = 0.04\\\\

P(Point | Non-used\ medication )=0.93\\\\ P(Point |No\ medication ) = 1 - 0.93 = 0.07

As per the given info we draw the tree diagram which is defined in the attachment file.

P ( test \ is\  positive ) = P( medication \ used ) \times P( Test \ positive | medication \ used ) + P( medication not \ used ) \times  P( Test\ positive | medication \ not \ used )

                  = ( 0.007 \times 0.96 ) + ( 0.993\times 0.07 )\\\\= 0.0762

P( medication \ used | test\ positive )= \frac{\textup{P( medication used ) *P( Test positive given medication  used )}}{\textup{P( medication used )}}  

= \frac{( 0.007\times 0.96 )}{0.0762}\\\\= 0.0882

8 0
3 years ago
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