3 years ago

Check all that apply please

Mathematics

1 answer:

luda_lava [24]3 years ago

7 0

Answer: A & B

<u>Step-by-step explanation:</u>

$\sqrt{5} *\sqrt{5} = \sqrt{5*5} = \sqrt{25} = 5$

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PLEASE GOD HELP ME!!!!

lara [203]

Another expression for the given rational function is $x =r^\frac{1}{2}s^\frac{1}{2}$

<h3>Indices expression</h3>

Given the rational function expressed as:

x = √rs

We can reconstruct the expression by writing it using exponents as shown;

$x =\sqrt{rs}=(rs)^{\frac{1}{2} }$

Separate to have:

$x =r^\frac{1}{2}s^\frac{1}{2}$

Hence another expression for the given rational function is $x =r^\frac{1}{2}s^\frac{1}{2}$

learn more on rational function here: brainly.com/question/1851758

#SPJ1

8 0

2 years ago

What two whole numbers is √29 between?<br> 3 and 4<br><br> 4 and 5<br><br> 5 and 6<br><br> 6 and 7

Nadya [2.5K]

Answer:

5 and 6

Step-by-step explanation:

Consider perfect square numbers either side of 29

25 < 29 < 36, thus

$\sqrt{25}$ < $\sqrt{29}$ < $\sqrt{36}$ , that is

5 < $\sqrt{29}$ < 6

5 0

3 years ago

Read 2 more answers

Please include equation and solution thanks

ehidna [41]

John is 31 and Jenny is 26

7 0

2 years ago

6 customers entered a store over the course of 18 minutes. At what rate were the customers entering the store in customers per m

alexandr1967 [171]

Answer:

3 minutes

Step-by-step explanation:

18 divided by 6 = 3 minutes

Hope this helps :)

7 0

3 years ago

Find all 6 trig functions given the terminal side goes through point (0,-3)

d1i1m1o1n [39]

So hmm notice the picture below

that's (0, -3)

now, keep in mind, adjacent is 0, opposite is -3, and hypotenuse, or radius, is 3

and recall $sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\ \quad \\

% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}$

8 0

3 years ago