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2 years ago

Evaluate the following expression when x = 6 and y = 2:

Mathematics

2 answers:

labwork [276]2 years ago

4 0

Answer:

5.5

Step-by-step explanation:

Yuri [45]2 years ago

3 0

X=6
y=2

(x^2+y^3)/(2+x)
(6^2+2^3)/(2+6)
(36+8)/(2+6)
44/8
5 1/2

Hope this helps :)

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Step-by-step explanation:

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2 years ago

Find the number of units that produce a maximum revenue, R =95x-0.1x^2, where R is the total revenue in dollars and x is the num

svp [43]

Answer:

$x=475$ units

Step-by-step explanation:

Method 1

The given revenue function is $R(x)=95x-0.1x^2$ .

We rewrite this function in the vertex form by completing the square.

$\Rightarrow R(x)=-0.1x^2+95x$ .

$\Rightarrow R(x)=-0.1(x^2-950x)+0$ .

We add and subtract half the coefficient of $x$ multiplied by a factor of $-0.1$ , which is $-0.1(-\frac{950}{2})^2=-0.1( -475)^2$ to get,

$R(x)=-0.1(x^2-950x)+-0.1(-475)^2--0.1(-475)^2 +0$ .

We factor $-0.1$ out of the first two expressions again to get,

$R(x)=-0.1(x^2-950x+(-475)^2)--0.1(-475)^2 +0$ .

We now got a perfect square.

$\Rightarrow R(x)=-0.1(x-475)^2+22562.5$ .

Therefore the maximum revenue occurs when $x=475$ units were sold.

Method 2

Use derivatives to find the x-value of the maximum point.

$R(x)=-0.1x^2+95x$

$R'(x)=-0.2x+95$

At maximum point,

$R'(x)=0$

$\Rightarrow -0.2x+95=0$ .

$\Rightarrow -0.2x=-95$ .

$\Rightarrow x=\frac{-95}{-0.2}$ .

$\Rightarrow x=475$ .

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