Answer:
5x + 1
Step-by-step explanation:
Answer:
B. 0.4542 to 0.5105
Step-by-step explanation:
A 90% confidence interval for p is calculated as:
![p-z_{\alpha /2}\sqrt{\frac{p(1-p)}{n} }\leq p\leq p+z_{\alpha /2}\sqrt{\frac{p(1-p)}{n} }](https://tex.z-dn.net/?f=p-z_%7B%5Calpha%20%2F2%7D%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%20%7D%5Cleq%20%20p%5Cleq%20p%2Bz_%7B%5Calpha%20%2F2%7D%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%20%7D)
This apply if n*p≥5 and n*(1-p)≥5
Where p is the proportion of sample, n is the size of the sample and
is equal to 1.645 for a 90% confidence.
Then, in this case p, n*p and n*(1-p) are calculated as:
![p=\frac{410}{850} =0.4824](https://tex.z-dn.net/?f=p%3D%5Cfrac%7B410%7D%7B850%7D%20%3D0.4824)
n*p = (850)(0.4824) = 410
n*(1-p) = (850)(1-0.4824) = 440
So, replacing values we get:
![0.4824-1.645\sqrt{\frac{0.4824(1-0.4824)}{850} }\leq p\leq 0.4824+1.645\sqrt{\frac{0.4824(1-0.4824)}{850} }](https://tex.z-dn.net/?f=0.4824-1.645%5Csqrt%7B%5Cfrac%7B0.4824%281-0.4824%29%7D%7B850%7D%20%7D%5Cleq%20%20p%5Cleq%200.4824%2B1.645%5Csqrt%7B%5Cfrac%7B0.4824%281-0.4824%29%7D%7B850%7D%20%7D)
![0.4824-0.0282\leq p\leq 0.4824+0.0282](https://tex.z-dn.net/?f=0.4824-0.0282%5Cleq%20p%5Cleq%200.4824%2B0.0282)
![0.4542\leq p\leq 0.5105](https://tex.z-dn.net/?f=0.4542%5Cleq%20p%5Cleq%200.5105)
It means that a 90% confidence interval for p is 0.4542 to 0.5105
Answer:
23
Step-by-step explanation:
Remember PEMDAS/order of operations (Parentheses, exponent, multiplication, division, addition, subtraction)
10*1/2+(-6)(-3)
10*1/2+18
5+18
23
You are correct
12.2^2 x 3.14 x 6.1 = 2850.9
Answer:
2.1
Step-by-step explanation:
3.4-2.8d+2.8d-1.3
3.4-1.3=2.1