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Furkat [3]
3 years ago
14

Blaise bought a used car for $3,250. He added a turbocharger that cost t dollars and a new air intake manifold that cost $178, b

ringing the total cost to $3,587. This situation can be represented by the equation $3,250 + $178 + t = $3,587. How much did the turbocharger cost?
Mathematics
1 answer:
BaLLatris [955]3 years ago
6 0

Answer:

t = $159

Step-by-step explanation:

3587-3250-178 = t

t = 159

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A job fair was held at the Student Union. 25% of the students who attended received job offers. Of all of the students at the jo
vovangra [49]

Answer:

A) Both events are not independent.

B) Both events are not mutually exclusive

C) 8.33%

D) 80%

Step-by-step explanation:

A) Both events are not independent. This is because, If B occurs it means that it is very likely that J will occur as well.

B) Both events are not mutually exclusive. This is because it is possible for both events J and B to occur at the same time.

C) we want to find the probability that Joe who is not a business student will receive the job offer.

This is;

P(J|Not B) = P(J & Not B)/P(Not B)

Now,

P(J & Not B) = P(J) – (P(B) × P(J | B))

25% of the students who attended received job offers. Thus; P(J) = 0.25

40% were from the College of Business. Thus;

P(B) = 0.4

Among the business students, 50% received job offers. Thus;

P(J|B) = 0.5

Thus;

P(J & Not B) = 0.25 - (0.4 × 0.5)

P(J & Not B) = 0.25 - 0.2

P(J & Not B) = 0.05

Since P(B) = 0.4

Then, P(Not B) = 1 - 0.4 = 0.6

Thus;

P(J|Not B) = 0.05/0.6

P(J|Not B) = 0.0833 = 8.33%

D) This probability is represented by;

P(B | J) = P(B & J)/P(J)

P(B & J) = (P(B) × P(J | B)) = (0.4 × 0.5) = 0.2

P(B | J) = 0.2/0.25

P(B | J) = 0.8 = 80%

5 0
3 years ago
Dawn has 5\6 yard of lace. She uses 4\5 of it on a dress and the rest on a jewel box. How much does she use on the jewel box
mr_godi [17]

Answer:

Jewelry box:  1/6 yard

Step-by-step explanation:

4/5 (not 4\5) of her 5/6 yard goes into a dress:   (4/5)(5/6 yd) = 2/3 yard.

This is the same as 4/6 yard.  The amount of lace remaining, to be used on a jewelry box, is 5/6 - 4/6, or 1/6 yard.

3 0
4 years ago
How do create a box plot
exis [7]
1. Gather your data
2. organize your data from least to greatest
3. find the median of the data set
4. find the first and third quartiles
5. draw a plot line
6. mark your first, second and third quartiles on the plot line you created
7. make a box by drawing a horizontal line connecting your quartiles
8. make your outliers 
9. connect your outliers to the box with the horizontal line 
and there you go

8 0
3 years ago
Find the numbers of yards in 63 feet
frutty [35]
You do 63/3 b/c there are 3 feet in one yard. I don't want to tell you answer b/c I want you to do math. CHALLENGE: Do the computation in your head. 
8 0
3 years ago
A sales associate farms a neighborhood with 750 homes. The owners seem to list their homes every six years. How many listings sh
jenyasd209 [6]

Answer:

50 homes

Step-by-step explanation:

Given that:

Total Number of homes = 750

Years at which home is listed = 6

Thus average listing per year = (total number of homes / years)

Average listing per year = 750 / 6

Average listing per year = 125 homes

If 40% of homes in the neighborhood can be listed :

0.4 * 125

= 50 homes

8 0
3 years ago
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