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stellarik [79]
2 years ago
14

Mr. Davis took his car to the repair shop. His total bill was $253. He was charged $48 for parts, and $5 for shop materials.

Mathematics
1 answer:
Serjik [45]2 years ago
3 0

Answer:

33.333333

Step-by-step explanation:

(253-(48+5))/6

(253-53)/6

200/6

33.333333

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Find x 6787+x=99798999?<br><br><br> dom join my remind ......28gc97d
wolverine [178]

Answer:

x=99792212

Step-by-step explanation:

get the x alone by subtracting 6787 from both sides

6787-6787+x=99798999-6787

x=99792212

Hope this helps!

5 0
2 years ago
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Turning 2 7/8 into a decimal
Jet001 [13]
2.875 would be the answer
8 0
3 years ago
The life in hours of a 75-watt light bulb is known to be normally distributed with standard deviation σ = 25 hours. A random sam
irina [24]

Answer: a) (1008.34,1019.658) b) (1009.24,1018.76)

Step-by-step explanation:

Since we have given that

n = 75

mean = 1014 hours

Standard deviation = 25 hours

At 95% two sided , z = 1.96

So, confidence interval would be

\bar{x}\pm z\dfrac{\sigma}{\sqrt{n}}\\\\=1014\pm 1.96\dfrac{25}{\sqrt{75}}\\\\=1014\pm 5.658\\\\=(1014-5.658,1014+5.658)\\\\=(1008.34,1019.658)

(b) Construct a 95% lower confidence bound on the mean life.

z = 1.65

So, confidence interval would be

\bar{x}\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=1014\pm 1.65\times \dfrac{25}{\sqrt{75}}\\\\=1014\pm 4.76\\\\=(1014-4.76,1014+4.76)\\\\=(1009.24,1018.76)

Hence, a) (1008.34,1019.658) b) (1009.24,1018.76)

4 0
3 years ago
In a large population of college-educated adults, the mean IQ is 118 with a standard deviation of 20. Suppose 200 adults from th
cricket20 [7]

Answer: 0.0793

Step-by-step explanation:

Let the IQ of the educated adults be X then;

Assume X follows a normal distribution with mean 118 and standard deviation of 20.

This is a sampling question with sample size, n =200

To find the probability that the sample mean IQ is greater than 120:

P(X > 120) = 1 - P(X < 120)

Standardize the mean IQ using the sampling formula : Z = (X - μ) / σ/sqrt n

Where;  X = sample mean IQ; μ =population mean IQ; σ = population standard deviation and n = sample size

Therefore, P(X>120) = 1 - P(Z < (120 - 118)/20/sqrt 200)

                                 = 1 - P(Z< 1.41)

The P(Z<1.41) can then be obtained from the Z tables and the value is 0.9207

Thus; P(X< 120) = 1 - 0.9207

                          = 0.0793

3 0
3 years ago
What is the area of this triangle?
dsp73

Answer:60

Step-by-step explanation:

a=13 b=13 c=10

Perimeter of =a+b+c

perimeter of =13+13+10

Perimeter of =36

S=36 ➗ 2

S=18

Area=√s(s-a)(s-b)(s-c)

Area=√18(18-13)(18-13)(18-10)

Area=√18(5)(5)(8)

Area=√(3600)

Area of =60

4 0
3 years ago
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