Answer:
Ayush's route is 0.7 km or 700m longer than Sumit route.
Step-by-step explanation:
Ayush's route is 1km 2hm long while sumit route is 2hm 30dam.
We know that,
1 km = 10 hm
1 dam = 0.1 hm
Using these conversions we get
Ayush's route = 1km 2hm = (1×10) hm + 2 hm = 12 hm
Sumit route = 2hm 30dam = 2 hm + (30×0.1) hm = 2 hm + 3 hm = 5 hm
Ayush's route is longer.
Difference = 12 hm - 5 hm = 7 hm = 0.7 km [1 km = 10 hm]
Hence, Ayush's route is 0.7 km or 700 m longer than Sumit route.
Answer:
12 boys
Step-by-step explanation:
From the above question:
Number of boys = 3
Number of girls = 2
Boys: Girls
3:2
Let :
a = boys
b = girls
Hence, a : b = 3 : 2
a/b = 3/2
Cross Multiply
2a = 3b .......... Equation 1
a = 3b/2
If four more girls join the class, there will be the same number of boys and girls
Hence,
a: b + 4 = 3 : 3
a/b + 4 = 3/3
Cross Multiply
3a = 3(b + 4)
3a = 3b + 12 ........ Equation (2)
From Equation 1: a = 3b/2
Substitute 3b/2 for a in Equation 2 we have:
3a = 3b + 12 .........Equation 2
3(3b/2) = 3b + 12
9b/2 = 3b + 12
Cross Multiply
9b = 2(3b + 12)
9b= 6b + 24
9b - 6b = 24
3b = 24
b = 8
Substitute 8 for b in Equation 1
a = 3b/2
a = 3 × 8/2
a = 24/2
a = 12
Therefore, the number of boys in the class is 12