Does anyone know the answer to this question?

Mathematics

1 answer:

Anon25 [30]3 years ago

4 0

I cannot answer your question.

You might be interested in

What is the equation of the line that represents the horizontal asymptote of the function f(x)=25,000(1+0.025)^(x)?

posledela

Answer:

The answer is below

Step-by-step explanation:

The horizontal asymptote of a function f(x) is gotten by finding the limit as x ⇒ ∞ or x ⇒ -∞. If the limit gives you a finite value, then your asymptote is at that point.

$\lim_{x \to \infty} f(x)=A\\\\or\\\\ \lim_{x \to -\infty} f(x)=A\\\\where\ A\ is\ a\ finite\ value.\\\\Given\ that \ f(x) =25000(1+0.025)^x\\\\ \lim_{x \to \infty} f(x)= \lim_{x \to \infty} [25000(1+0.025)^x]= \lim_{x \to \infty} [25000(1.025)^x]\\=25000 \lim_{x \to \infty} [(1.025)^x]=25000(\infty)=\infty\\\\ \lim_{x \to -\infty} f(x)= \lim_{x \to -\infty} [25000(1+0.025)^x]= \lim_{x \to -\infty} [25000(1.025)^x]\\=25000 \lim_{x \to -\infty} [(1.025)^x]=25000(0)=0\\\\$

$Since\ \lim_{x \to -\infty} f(x)=0\ is\ a\ finite\ value,hence:\\\\Hence\ the\ horizontal\ asymtotes\ is\ at\ y=0$

5 0

3 years ago

While testing a new vaccine, a lab technician noticed that the number of bacteria reduced by half every minute. How long does it

son4ous [18]

To start, find your equation, n=3000(.5)^t, n being your number of bacteria and t being your time. Now plug in 375 for n and solve for t, 375=3000(.5)^t, .125=.5^t, $t=log_{.5} .125=3$ . This means your answer is 3 minutes. To check it, plug it into your equation. n=3000(.5)^t=3000(.125)=375