I hope this picture helps. I'll elaborate if needed!
URHENT I NEED HELP WITH THESE I NEED THE FIRST QUESTION.
1 answer:
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**y=x+2
when x=0,y=2; A(0,2)
when x=1,y=3; B(1,3)
**y=-x+8
when x=0,y=8; C(0,8)
when x=5,y=-3; D(5,-3)
The solution from the graph is S(2,4).
when x=0,y=2; A(0,2)
when x=1,y=3; B(1,3)
**y=-x+8
when x=0,y=8; C(0,8)
when x=5,y=-3; D(5,-3)
The solution from the graph is S(2,4).
First, you solve the square root:
Knowing that the square root of a negative number doesn't exist:
is your answer.
Hope it helped,
Happy homework/ study/ exam!
Knowing that the square root of a negative number doesn't exist:
Hope it helped,
Happy homework/ study/ exam!