Can u help me with 2&4
1 answer:
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Answer:
μ = 235.38
σ = 234.54
Step-by-step explanation:
Assuming the table is as follows:
This is an example of grouped data, where a range of values is given rather than a single data point. First, find the total frequency.
n = 339 + 86 + 55 + 18 + 11 + 8 + 3
n = 520
The mean is the expected value using the midpoints of each range.
μ = (339×100 + 86×300 + 55×500 + 18×700 + 11×900 + 8×1100 + 3×1300) / 520
μ = 122400 / 520
μ = 235.38
The variance is:
σ² = [(339×100² + 86×300² + 55×500² + 18×700² + 11×900² + 8×1100² + 3×1300²) − (520×235.38²)] / (520 − 1)
σ² = 55009.7
The standard deviation is:
σ = 234.54
Answer:
(a)31.42 inches
(b)942.48 Square Inches
Step-by-step explanation:
Given a sector of a circle with the following dimensions:
Radius of the circle =60 inches
Central Angle of the sector =30°
(a)Arc Length
Arc Length
(b)Area of the sector
Area of the sector
Answer:
The answers are in solutions.
Step-by-step explanation:
- Four businessmen invested a sum of Rs. 250,000 in the ratio of 3:5:7:10 to start a new business.
(i) The amount invested by each businessman is;
<u>1^st businessman invested:</u>
<u />
Rs. 30,000
<u>2^nd businessman invested:</u>
<u />
<u /> = Rs. 50,000
<u>3^rd businessman invested:</u>
<u />
<u /> = Rs. 70,000
<u>4^th businessman invested:</u>
<u />
= Rs. 100,000
- If they gained Rs. 50,000
(ii) The profit each one of them got is;
<u>1^st businessman got:</u>
<u />
<u /> = Rs. 6,000
<u>2^nd businessman got:</u>
<u />
<u /> = Rs. 10,000
<u>3^rd businessman got:</u>
<u />
<u /> = Rs. 14,000
<u>4^th businessman got:</u>
= Rs. 20,000