Question

Sonya found that x = - 4/3 is one solution of (6x + 4)2 = ?. The other solution is x = ? .

Answer 1

Solution: The value of (?) is 16 and the other value of x is 0.

Explanation:

Let the value of (?) is C.

It the given equation is $(6x+4)^2=C$. It can be written as $(6x+4)^2-C=0$

Since $x=\frac{-4}{3}$ is the solution of the given equation, therefore $x=\frac{-4}{3}$ will satisfies the given equation.

Put $x=\frac{-4}{3}$

$(6(\frac{-4}{3}) +4)^2-C=0\\(-8+4)^2-C=0\\{-4}^2-C=0\\C=16$.

The given equation become $(6x+4)^2+16=0$.

$(6x+4)^2=16$

$6x+4=4\\6x=0\\x=0$

$6x+4=-4\\6x=-8\\x=\frac{-4}{3}$

Therefore the value of (?) is 16 and the other value of x is 0.

Answer 2

Answers are 16 and 0