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babymother [125]
4 years ago
14

Sheena wants to list the outer planets from smallest to largest. which is correct?

Physics
2 answers:
jasenka [17]4 years ago
7 0

The outer planets of the Solar System are:

- Jupiter (radius: 69,911 km)

- Saturn (radius: 58,232 km)

- Uranus (25,362 km)

- Neptune (24,622 km)

By looking at the radius of each planet, we can arrange them in order from the smallest to the largest, and we get:

1) Neptune

2) Uranus

3) Saturn

4) Jupiter

Scrat [10]4 years ago
5 0
Sheena should list down the planet in the same order below:
1. Mercury
2. Mars
3. Venus
4. Earth
5. Neptune
6. Uranus
7. Saturn 
8. Jupiter
This is the correct arrangement of outer planets starting from smallest to largest. 
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Student A states that when she sits down on a chair, she is exerting a force on the chair and that is all that happens. Student
zvonat [6]

Answer:

C

Explanation:

I got it right on the test !!

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3 years ago
The coefficient of linear expansion of copper is 17 x 10^-6 K-1. A block of copper 30 cm wide, 45 cm long, and 10 cm thick is he
schepotkina [342]

Answer:

The change in volume is 6.885\times 10^{- 5}\

Solution:

As per the question:

Coefficient of linear expansion of Copper, \alpha = 17\times 10^{- 6}\ K^{- 1}

Initial Temperature, T = 0^{\circ} = 273 K

Final Temperature, T' = 100^{\circ} = 273 + 100 = 373 K

Now,

Initial Volume of the block, V = 30\times 45\times 10\times 10^{- 6}\ m^{3} = 0.0135\ m^{3}

V' = V(1 + \gamma \Delta T)

\gamma = 3\alpha

V' = V(1 + 3\alpha \Delta T)

where

V' = Final volume

V' - V= 0.0135\times 17\times 10^{- 6} \times (T' - T))

\Delta V= 0.0135\times 3\times 17\times 10^{- 6} \times (373 - 273)) = 6.885\times 10^{- 5}\

7 0
3 years ago
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Mumz [18]
No se ha da han dicho nada más de lo dicho y han ido de vuelta y han dicho nada más de que se pueda hacer el favor del niño
4 0
3 years ago
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What would be the result of an alpha particle coming into a magnetic field?
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8 0
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a shell fired from a cannon at 60 ° from horizontal strikes a target 20m high at a distance 80m. Calculate the initial velocity
stich3 [128]

consider the motion along the X-direction

X = horizontal displacement = 80 m

V_{ox} = initial velocity along the x-direction = v Cos60

t = time of travel

using the equation

X = V_{ox}   t

80 = (v Cos60) (t)

t = 160/v                                         eq-1


consider the motion in vertical direction :

Y = vertical displacement = 20 m

V_{oy}  = initial velocity in Y-direction = v Sin60

a = acceleration = - 9.8 m/s²

t = time of travel = 160/v

using the equation

Y = V_{oy}  t + (0.5) a t²

20 = (v Sin60) (160/v) + (0.5) (- 9.8) (160/v)²

v = 32.5 m/s

4 0
3 years ago
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