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Dmitriy789 [7]
3 years ago
14

two people choose different reference points to specify an object's position. does this difference affect the coordinates of the

object?
Physics
1 answer:
Nuetrik [128]3 years ago
7 0

Answer:

no

Explanation:

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A train of mass 320000 kg accelerate uniformly from rest. It takes 57 s to travel a distance of 810 m in a straight line. Find t
Nastasia [14]

Answer:

160,000 N

Explanation:

Given:

m = 320,000 kg

v₀ = 0 m/s

a = constant

t = 57 s

Δx = 810 m

Find: Fnet

Apply Newton's second law:

∑F = ma

Fnet = ma

To find Fnet, we must first find the acceleration.

x = x₀ + v₀ t + ½ at²

810 m = 0 m + (0 m/s) (57 s) + ½ a (57 s)²

a = 0.50 m/s²

Fnet = (320,000 kg) (0.50 m/s²)

Fnet = 160,000 N

8 0
4 years ago
If the forces acting on an system produce a net force, what can we say about these forces
lutik1710 [3]
Net force refers to the (vector) sum of all the forces acting on something. It's a mathematical construction, so it's not a single identifiable force. The forces themselves are real, but the net force is not an actual force.

Hope this helps you out.
8 0
3 years ago
SIL. TUILE I JUMU<br>Write down your own examples for each of the different effects of forces.​
Harrizon [31]

Answer:

magnetic force

Explanation:

when some one gets charged up by maybe static eletricity the person will sustain the energy and the energy will make a force field around the person which can and will attract paper and he will be attractive

5 0
3 years ago
Read 2 more answers
How many joules is one calorie?
Stels [109]
4184 joules is one calorie
8 0
3 years ago
Free electromagnetic oscillations occur in an electrical circuit. Knowing the characteristic dimensions of the elements, L=20mH
kirill115 [55]

Answer:

a. 0.199 ms b. 5.03 kHz c. 0.1 mJ

Explanation:

a. The period of oscillation of an L-C circuit is T = 2π√(LC) where L = inductance = 20 mH = 20 × 10⁻³ H and C = capacitance = 0.005 mF = 5 × 10⁻⁶ F.

So, T = 2π√(LC)

= 2π√(20 × 10⁻³ H × 5 × 10⁻⁶ F)

= 2π√(100 × 10⁻¹¹)

= 2π√(10 × 10⁻¹⁰)

= 2π(3.16 × 10⁻⁵)

= 19.87 × 10⁻⁵

= 1.987 × 10⁻⁴ s

= 1.99 × 10⁻⁴ s

= 0.199 × 10⁻³ s

= 0.199 ms

b. frequency , f = 1/T where T = period = 0.199 × 10⁻³ s.

So, f = 1/0.199 × 10⁻³ s

= 5.03 × 10³ Hz

= 5.03 kHz

c. The electromagnetic energy E = 1/2Li² where L = inductance = 20 × 10⁻³ H and i = current = 100 mA = 0.1 A

So, E = 1/2Li²

= 1/2 × 20 × 10⁻³ H × (0.1 A)²

= 0.1 × 10⁻³ J

= 0.1 mJ

3 0
3 years ago
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