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Triss [41]
3 years ago
12

Problem 7:__deletededc326999bef85931fda5d1ab0d68e21218f27b46f4f11ab80872358251b584ddeleted__ 0N86-C1-52-40-A837-22820 If object

A is twice the mass of object B what can be said about their kinetic energies just as they hit the ground
Physics
1 answer:
laila [671]3 years ago
3 0

Answer:

the kinetic energy of body B is twice the kinetic energy of body A

Explanation:

The kinetic energy of a body is given by

          K = ½ m v²

If two objects leave the same point, suppose that at the same height when they reach the ground they have the same velocity.

Therefore if the mass of body b is twice the mass of body A

          m_{b} = 2 m_{a}

         K_{b} = ½ (2 m_{a}) v²

          K_{b} = 2 (½ m_{a} v²)

          K_{b} = 2 K_{a}

therefore the kinetic energy of body B is twice the kinetic energy of body A

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A sled is pulled at a constant velocity across a horizontal snow surface. If a force of 100 N is being applied to the sled rope
tangare [24]

Answer:

60.18 N

Explanation:

Given that:

The force applied on the sled = 100 N

Suppose, the angle between the sled rope and the ground = 53°

The horizontal force which acts  in the horizontal direction can be expressed as:

F_x = F \ cos \theta

F_x = 100 \ cos (53)

F_x = 60.18 \ N

But if the angle between the sled rope is parallel to the ground. Then, we use an angle on a straight line which is = 180°

F_x = F \ cos \theta

F_x = 100 \ cos (180)

= 100 × -1

= -100 N

3 0
2 years ago
A 0.50-kg croquet ball is initially at rest on the grass. When the ball is struck by a mallet, the average force exerted on it i
NeTakaya

The impulse given to the ball is equal to the change in its momentum:

J = ∆p = (0.50 kg) (5.6 m/s - 0) = 2.8 kg•m/s

This is also equal to the product of the average force and the time interval ∆t :

J = F(ave) ∆t

so that if F(ave) = 200 N, then

∆t = J / F(ave) = (2.8 kg•m/s) / (200 N) = 0.014 s

7 0
1 year ago
A 4-kilogram ball moving at 8 m/sec to the right collides with a 1-kilogram ball at rest. After the collision,
elena-14-01-66 [18.8K]
Conservation of momentum: total momentum before = total momentum after

Momentum = mass x velocity

So before the collision:
4kg x 8m/s = 32
1kg x 0m/s = 0
32+0=32

Therefore after the collision
4kg x 4.8m/s = 19.2
1kg x βm/s = β
19.2 + β = 32

Therefore β = 12.8 m/s
4 0
3 years ago
What is the total energy equation?
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The total energy equation would be Kinetic energy+Potential energy
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False. What actually determines the properties of elements are the electrons, or aka valence electrons. They are used to bond, which determines its properties. 
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