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Triss [41]
3 years ago
12

Problem 7:__deletededc326999bef85931fda5d1ab0d68e21218f27b46f4f11ab80872358251b584ddeleted__ 0N86-C1-52-40-A837-22820 If object

A is twice the mass of object B what can be said about their kinetic energies just as they hit the ground
Physics
1 answer:
laila [671]3 years ago
3 0

Answer:

the kinetic energy of body B is twice the kinetic energy of body A

Explanation:

The kinetic energy of a body is given by

          K = ½ m v²

If two objects leave the same point, suppose that at the same height when they reach the ground they have the same velocity.

Therefore if the mass of body b is twice the mass of body A

          m_{b} = 2 m_{a}

         K_{b} = ½ (2 m_{a}) v²

          K_{b} = 2 (½ m_{a} v²)

          K_{b} = 2 K_{a}

therefore the kinetic energy of body B is twice the kinetic energy of body A

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3 years ago
Two trains on separate tracks move toward each other. Train 1 has a speed of 109 km/h; train 2, a speed of 99.0 km/h. Train 2 bl
Rufina [12.5K]

Answer:

f_o=592.36 Hz

Explanation:

Given that

Train 1 (observer):

Speed = 109 km/h

Train 2 (source):

Speed = 99 km/h

Train 2 emitting frequency = 500 Hz

We know that observer and source are moving toward each other, then frequency heard by observer can be given as follows

f_o=\left(\dfrac{C+V_o}{C-V_s}\right)f_s

Where C is the velocity of sound  (C=1225 Km/h)

Now by putting the values

f_o=\left(\dfrac{C+V_o}{C-V_s}\right)f_s

f_o=\left(\dfrac{1225+109}{1225-99}\right)\times 500

f_o=592.36 Hz

4 0
3 years ago
The motion of a piston in an auto engine is simple harmonic. If the piston travels back and forth over a distance of 10 cm and t
chubhunter [2.5K]

Answer:

Maximum force will be 29040 N

Explanation:

We have given mass of the piston m = 1.5 kg

Amplitude A = 10 cm = 0.1 m

Angular speed \omega =4200rpm=\frac{2\times 3.14\times 4200}{60}=440rad/sec

We know that angular speed is given by \omega =\sqrt{\frac{k}{m}}

440=\sqrt{\frac{k}{1.5}}

Squaring both side

193600=\frac{k}{1.5}

k = 290400 N/m

Now force is given by F=kA=290400\times 0.1=29040N

3 0
3 years ago
A square brass plate has large circular hole cut in its centre. If the plate is heated, it will expand. Will the diameter of the
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3 years ago
A ball is thrown with a velocity of 40 m/s at an angle of 30° above the horizontal and attains a certain range R. At what other
choli [55]

Answer:

This ball will attain the same range at 60°.

Explanation:

Projectile motion: when an object is thrown in such a way that it form an angle with horizon, the force act on it that is the acceleration due gravity. This type of motion is known as projectile motion.

Range: The horizontal distance is covered by an object.

Range =\frac{u^2 sin2\theta}{g}

u = initial velocity = 40 m/s

θ = 30°

g = gravity =9.8 m/s²

Range=\frac{40^2\times sin(2\times 30^\circ)}{9.8}

         =\frac{800\sqrt{3} }{9.8}

Next,

Range =\frac{800\sqrt{3} }{9.8} and u = 40 m/s

sin2\theta =\frac{Range \times g}{u^2}

\Rightarrow  sin2\theta =\frac{\frac{800\sqrt{3} }{9.8} \times 9.8}{40^2}

\Rightarrow sin 2\theta =\frac{\sqrt{3} }{2}

\Rightarrow sin 2\theta = sin 120^\circ

\Rightarrow \theta =120^\circ

\Rightarrow \theta =60^\circ

This ball will attain the same range at 60°.

3 0
3 years ago
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