The answer is density-dependent factor
Answer:
Seaweeds, shrimps, salmon
Explanation:
The rapid increase in the human population day by day has led to the increased usage of marine plants and animals. Due to this, the population f some marine plants and animals is declining to threatening levels.
To overcome his problem, scientists have devised the method of mariculture. This technique involves raising aquatic plants and animals in artificial lakes or ponds containing salty water just like in the oceans.
Some of these plants and animals are:
- Sea weeds: People might think that they do not consume sea weeds but it is actually present in most of our daily use products like toothpaste, ice creams and even in some automobiles. Many people from the world consume sea weeds as food. Hence, they are being raised in maricultures.
- Shrimps: Shrimps are favourite sea food among many people belonging to different areas. Hence, there population is declining due to which they need to be raised artificially.
- Salmon: The salmon is a kind of fish common to almost every nation. Hence, to meet the demands of people they need to be produced in maricultures.
<em>Protein synthesis is the process whereby biological cells generate new proteins and it is balanced by the loss of cellular proteins via degradation or export.</em>
It helps the body build muscles and protects from germs and virus.
Answer:
Option (A), (B), (D) and (F).
Explanation:
Bacteria are involved in the domains of eubacteria and archaea. Bacteria are different from the other organism and shows different in the chemical and cellular structure of the cell.
The translation elongation factors are different in bacteria and other organisms. The translation factors of bacteria are EF-Tu and EF-Ts whereas the eukaryotic elongation factors are eEF-1 subunit α and eEF-1 subunit βγ. A single RNA pol is present in bacteria and three different RNA pol is present in eukaryotes. Peptidoglycan is present in prokaryotes. Phospholipids contain ester linkage in bacteria and ether linkage in archaea.
Thus, the correct answer is option (A), (B), (D) and (F).
