Answer:
this is assuming brown eyes are dominant
6a 9/16
b.3/16
c 3/16
d. 1/16
Explanation: there might be an easy way to calculate it but I draw it out and use the dominance and lettering and just count I used slide 5 as a starting point
to do more than this would require seeing the square on slide 1 they are referring to as it is specific to 2 parents
4. a Bb and bb
b. bb and bb
5. BBEE BBEe BbEEBbEe
BBEe BBee BbEe Bbee
BbEE BbEe bbEE bbEe
BbEe Bbee bbEe bbee
2 a Bb
b Brown hair
c. Bb and brown hair
d. blonde hair
e. BB
3. A50%
c. 50%
25%
75%
25%
Scientists so far haven’t managed to figure that out .
Answer:
15.21 %
Explanation:
If we recall the basic formula of Hardy-Weinberg's equilibrium ; we have the following below:
p + q = 1
p² + 2pq + q² = 1
where;
p = frequency of the dominant allele in the population
q = frequency of the recessive allele in the population
p² = percentage of homozygous dominant individuals
q² = percentage of homozygous recessive individuals
2pq = percentage of heterozygous individuals
Given that p= 0.68 and q = 0.39
the percentage of the homozygous recessive genotype (q² ) will be
(0.39)² = 0.1521
= 0.1521 × 100
= 15.21 %
∴ the percentage of the population that has a homozygous recessive genotype = 15.21 %
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