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xxMikexx [17]
3 years ago
6

Ordinary cell division produces two daughter cells that are genetically identical. This type of cell division is important for a

ll of the following functions EXCEPTA) growth of a multicellular organism.B) cell replacement.C) production of sperm and eggs.D) asexual reproduction.
Biology
1 answer:
Ratling [72]3 years ago
8 0

Answer:

C) production of sperm and eggs

Explanation:

Sperms and eggs are the male and female gametes respectively. Formation of sperms and egg cells require meiotic cell division. Meiosis in sperm mother cells and egg mother cells reduces the chromosome number of half in the sperms and eggs. Meiosis also adds new gene combinations in these gametes by the process of crossing over.  

Mitosis cannot reduce the chromosome number to half in the sperms and eggs. Absence of crossing over in mitosis leads to the formation of genetically identical progeny cells from mitosis.  

Hence, mitosis can not form sperms and egg cells.  If it does, the sperms and egg cells would not have genetic variations and there would be doubling of chromosome number with each round of sexual reproduction.

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2 years ago
NEED HELP FOR 100 POINTS AND BRAINLIEST PLEASEEE
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Answer:

this is assuming brown eyes are dominant

6a 9/16

b.3/16

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d. 1/16

Explanation: there might be an easy way to calculate it but I draw it out and use the dominance and lettering and just count I used slide 5 as a starting point

to do more than this would require seeing the square on slide 1 they are referring to as it is specific to 2 parents

4. a Bb and bb

b. bb and bb

5. BBEE BBEe BbEEBbEe

BBEe BBee BbEe Bbee

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2 a Bb

b Brown hair

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6 0
3 years ago
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Ronch [10]
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4 0
3 years ago
The gene frequency for a dominant allele is 0.68 and the recessive allele is 0.39. What percent of the population has a homozygo
Alinara [238K]

Answer:

15.21 %

Explanation:

If we recall the basic formula of Hardy-Weinberg's equilibrium ; we have the following below:

p + q = 1

p² + 2pq + q² = 1

where;

p = frequency of the dominant allele in the population

q = frequency of the recessive allele in the population

p² = percentage of homozygous dominant individuals

q² = percentage of homozygous recessive individuals

2pq = percentage of heterozygous individuals

Given that p= 0.68 and q = 0.39

the percentage of the homozygous recessive genotype (q² ) will be

(0.39)² = 0.1521

= 0.1521 × 100

= 15.21 %

∴ the percentage of the population that has a homozygous recessive genotype = 15.21 %

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3 years ago
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