3 years ago

What is the solution to the inequality (−4+8x)+3>x/−4 ?

Mathematics

1 answer:

NARA [144]3 years ago

4 0

(−4+8x)+3>x/−4

Remove the parenthesis and simplify the left side:

8x - 1 > x /-4

Add x/4 to each side:

8x + x/4 -1 > 0

Simplify the left side by combining 8x and x/4 as a fraction with a common denominator:

33x/4 -1 > 0

Add 1 to both sides:

33x/4 > 1

Multiply both sides by 4:

33x > 4

Divide both sides by 33:

x > 4/33

You might be interested in

Which is the x-intercept for 4x-2y = 16? A) (4, 0) B (0, 4) C (0, 8) D (-8, 0)

galben [10]

Answer:

Just plug in each point for the x and y and find which point is valid

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

1 of 20 (19 complete)

Marina86 [1]

I hope this helps you find the answer you're looking for

8 0

3 years ago

Evaluate the algebraic expression for the given variable -x- -3,x=-5

Dvinal [7]

Here u go, u replace x by the number

6 0

3 years ago

Solve for x <img src="https://tex.z-dn.net/?f=4%20%20%7Bx%7D%5E%7B2%7D%20%20%3D%207x%20%2B%202" id="TexFormula1" title="4 {x

Alina [70]

$\bf 4x^2=7x+2\implies 4x^2-7x-2=0\implies (4x+1)(x-2)=0 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 4x\cdot x=\boxed{4x^2}~\hfill (1)(-2)=\boxed{-2}\hfill (4x\cdot -2)+(1\cdot x)=\boxed{-7x} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} 4x+1=0\implies 4x=-1\implies &x=-\cfrac{1}{4}\\[1em] x-2=0\implies &x=2 \end{cases}$

7 0

3 years ago

There are 4 consecutive odd integers with a sum of 128

Free_Kalibri [48]

29, 31, 33, & 25. Those are all odd and if added up equal 128

5 0

3 years ago

Read 2 more answers