The laws governing intellectual property are where common-law and code-law systems most obviously diverge.
<h3>
What is intellectual property ?</h3>
The collection of intangible assets that a company or person possesses and is legally entitled to guard against illegal use or application by third parties is referred to as intellectual property.
The concept of intellectual property was developed on the premise that some works produced by the human mind should be afforded the same legal protections as material possessions.
Hence, the difference between common-law and code-law systems is found in the laws pertaining to intellectual property.
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Answer:
external stimulus : Cue
restoration of buying impulse: Reinforcement
strong internal stimulus: Drive
action taken by prospect: Response
Explanation:
Answer: See explanation
Explanation:
The general journal entries necessary to adjust the interest accounts at December 31 will be:
1. December 31:
Debit: Interest Expenses = $8,000 × 9% × 51/ 360 = $102
Credit: Interest payable = $102
(To accrue interest expenses for the note issued on November 10).
2. December 31:
Debit: Interest Expenses = $12,000 × 10% ×30/360 = $120
Credit: Interest payable = $120
(To accrue interest expenses for the note issued on December 1)
3. December 31:
Debit: Interest Expenses = $12,000 × 10% × 11/360 = $36.67
Credit: Interest payable = $36.67
(To accrue interest expenses for the note issued on December 20).
The cost of the car after 5 years from then, will be $15652.99.
Given here, the depreciation every year(r) 7% or 0.07per year, asset cost (of the car) is $22,500 and time period (n) is 5 years.
The value after 5 years can be calculated as,
Depreciated value = asset cost ×(1-r) n
= 22500 × (1-0.07) 5
= 15652.99$.
Thus, the car worths 15652.99$ after 5 years.
The worth of an asset after its useful life is expired, as it is diminished over time by depreciation, is its depreciated cost. The asset’s worth is continuously diminished by figuring out how much it will cost to depreciate it, but the depreciated cost technique always permits accounting records to represent an item at its current value.
Depreciation is an accounting technique for spreading out the expense of a tangible item over the course of its useful life.
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Answer:
Amount of interest = $ 300
Explanation:
Given:
Total number of month = 3 months (Oct, Nov and Dec)
Amount borrow = $20,000
Interest rate = 6%
Find:
Amount of interest
Computation:
Amount of interest = $20,000 x 6% x 3 months / 12 months
Amount of interest = $ 300
