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spin [16.1K]
4 years ago
12

What is the radius of a circle whose equation is x2 y2 – 10x 6y 18 = 0?

Mathematics
2 answers:
HACTEHA [7]4 years ago
6 0
Hello,

x²+y²-10x+6y+18=0
==>(x²-2*5x+25)+(y²+2*3y+9)+18-25-9=0
==>(x-5)²+(y+3)²=16

Radius is 4.
Center (5,-3)
Mumz [18]4 years ago
4 0

The correct answer is:

4 units

The radius of the circle is 4 units.

|Huntrw6|

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M∠=6, m∠=+20, and m∠=40+3. List the sides of △ in order from shortest to longest.
oksian1 [2.3K]

Answer:

m∠=6, ,m∠=+20,m∠=40+3

the larger the angle, the larger the side

7 0
3 years ago
How many significant figures are there in the number 3,460?
AleksandrR [38]

Answer:

3 figures

Step-by-step explanation:

Just follow these steps!

Non-zero digits are always significant.

Any zeros between two significant digits are significant.

A final zero or trailing zeros in the decimal portion ONLY are significant.

4 0
3 years ago
1) Carefully follow the steps to find the solution to the three equation system.
rjkz [21]

Step-by-step explanation:

a. we simply subtract 3. from 2.

x + 2y + z = 15

- -3x + y + z = 2

--------------------------

4x + y 0 = 13

b. we multiply 3. by 3 and then subtract from 1.

2x - 4y + 3z = -7

- -9x + 3y + 3z = 6

-----------------------------

11x - 7y 0 = -13

c. we multiply the result of a. by 7, and then simply add a. and b., because the y terms have different signs already.

28x + 7y = 91

+ 11x - 7y = -13

--------------------------

39x 0 = 78

39x = 78

x = 2

d. we use this x = 2 in the result of a.

4×2 + y = 13

8 + y = 13

y = 5

e. using x = 2 and y = 5 in 2.

2 + 2×5 + z = 15

2 + 10 + z = 15

12 + z = 15

z = 3

the solution is therefore (2, 5, 3).

8 0
1 year ago
Read 2 more answers
When sampled, 135 out of 200 people said they were runners. If the sample was taken from a population of 17,000 people, which of
Korolek [52]
D.  11,475  (135/200= .675 =67.5 %) (67.5% x 17,000 = 11,475) 
6 0
4 years ago
Can someone help me please? the last point of the first graph ends on 6 ​
just olya [345]

Answer:

a) Yes

b) for reference, draw the line y = x, and reflect it over that, this reflection will be your inverse. Or switch the x and y values of each point of the function.

Here is a photo of the original function in black, it's inverse in red, and the line of reflection y = x in blue:

c) No, because it fails the vertical line test, when you draw a vertical line across the inverse function, it hits it more than once.

d) Domain of the original function: -6 ≤ x ≤ 6 ; x(the domain) is greater than or equal to -6 and less than or equal to 6.

e) Domain of inverse function: 0 ≤ x ≤ 4 ; x(the domain) is greater than or equal to 0 and less than or equal to 4.

f) Range of the original function: 0 ≤ y ≤ 4 ; y(the range) is greater than or equal to 0 and less than or equal to 4.

e2) Range of the inverse function: -6 ≤ y ≤ 6 ; y(the range) is greater than or equal to -6 and less than or equal to 6.

f2) x-intercept of original function: -6

g) y-intercept of the inverse function: -6

h) x-intercept of the inverse function: 4

i) y-intercept of the original function: 4

j) (2,2) or any point where the x, and y are the same within the function, or the point where the function intersects y = x.

5 0
3 years ago
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