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spin [16.1K]
4 years ago
12

What is the radius of a circle whose equation is x2 y2 – 10x 6y 18 = 0?

Mathematics
2 answers:
HACTEHA [7]4 years ago
6 0
Hello,

x²+y²-10x+6y+18=0
==>(x²-2*5x+25)+(y²+2*3y+9)+18-25-9=0
==>(x-5)²+(y+3)²=16

Radius is 4.
Center (5,-3)
Mumz [18]4 years ago
4 0

The correct answer is:

4 units

The radius of the circle is 4 units.

|Huntrw6|

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-15+5x= 20

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Can anyone solve all of these? Sorry it’s a bad picture.
Vladimir [108]

Answer:

N. -104

S. 112

O. -59

Step-by-step explanation:

i will try my best to solve all of them, but may set up some problems that are ready to be solved.

N. Find (f + g)(8) what this question means is to find the function of <em>f</em> and <em>g </em>added together. the 8 is equal to x, so you will first combine the functions f and g together, and then we will worry about 8

f(x) =3x+4 and g(x) = -2x²-4 (f+g)(x) is the same as the functions f and g added together:

(3x + 4) + (-2x²-4) = -2x² + 3x

now we will set x = 8 and solve

(f+g)(8)= -2(8)² + 3(8) --> -2(64) + 24 = -104 < this is our answer for (f+g)(8)

S. Find (f × g)(-4) this is similar to the above problem, except it is multiplication. we will solve for (f*g) first

f(x) = x + 2 and g(x) = x³-2x

(f×g)(x) = (x+2)(x³-2x) <-- use FOIL to solve and we get:

x^4 + 2x³ - 2x² - 4x and now we subtitute -4 for x

(f×g)(-4) = (-4)^4 + 2(-4)³ - 2(-4)² - 4(-4) = 112 < this is our answer for (f*g)(-4)

O. Find (f - g)(4) again, similar to the above problems besides the sign

f(x) = 4x-3 and g(x) = x³+2x

(f - g)(x) = (4x - 3) - (x³ + 2x) <-- remember to distribute the negative sign in front of x³ + 2x, or else you will not get the correct answer

this is equal to: -x³+2x-3 and now we put x = 4

-(4)³ + 2(4) -3 = -59 < this is our answer for (f - g)(4)

edit: was able to add the answers

I. Find (f×g)(1)I will set this problem up for you because I have done a similar problem for S

f(x) = x²+4 + 2x and g(x) = -3x+2

(f×g)(x) = -3x³-4x² - 8x + 8<-- x = 1 in this equation, so solve for that and you should have your answer

W. Find (f+g)(10) again, I will set this problem up for you again since there is a similar problem for N

f(x) = 3x+3 and g(x) = -4x+1

(f+g)(x) = 3x+3 + (-4x+1) = -x + 4<-- x = 10 in the equation and you just have to plug in the value 10 for x and that would be the answer

B. says I have swear words in this answer, but the answer is -16, please let me know if you would like an explanation for this question

H. Find(f × g)(-4)i will solve this problem entirely instead of setting it up like the last similar one

f(x) = 2x - 1 and g(x) = 3x - 3

(f×g)(x) = (2x-1)(3x-3) = 6x² - 9x + 3 <-plug in -4 for x

(f×g)(-4) = 6(-4)² -9(-4) + 3 = 135 <this is our answer for (f*g)(-4)

K.Find (f×g)(-1) i will solve this problem as well

f(x) = x²+3 and g(x)=4x-3

(f×g)(x) = (x²+3)(4x-3) = 4x³ - 3x² + 12x - 9

(f×g)(-1) = 4(-1)³ - 3(-1)² + 12(-1) - 9 = -28 <answer for (f×g)(-1)

T. Find f(g(2))the meaning of this is f composed of g, it can also be stylized as (fºg). this means that the x value of the function g is 2, and the solution to the function g is the x value of the function f. so lets solve this:

f(x) = 3x+2 and g(x) = 2x² + 5 we will solve g(2) first

g(2) = 2(2)² + 5 = 2(4) + 5 = 8 + 5 = 13so g(2) = 13

now we plug the solution to g(2) into f(x)

f(13) = 3(13)+2 = 39 + 2 = 41 <this is our answer to f(g(2))

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It is believed that students who begin studying for final exams a week before the test score differently than students who wait
olga55 [171]

Answer:

H0 : μ1 = μ2

H0 : μ1 < μ2

Step-by-step explanation:

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Early studiers, group 1, mean μ1

Late studiers, group 2 ; mean, μ2

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