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PilotLPTM [1.2K]
3 years ago
11

What is the solution set of the equation x²+2x-24=0?

Mathematics
2 answers:
kirill115 [55]3 years ago
5 0
Simple...

you have x^{2} +2x-24=0

AND WORK IS ATTACHED!! :D

Montano1993 [528]3 years ago
4 0
The correct answer is x=6
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PLEASE HELP IT IS DUE NOW!!!!<br> will give brainliest
vodomira [7]

Answer:

5.

2.4 = E

-1 4/5 = B

-0.2 =C

-2 3/5 = A

0.6 = D

6. one line under -1

Step-by-step explanation:

5. On the number line each short line is by 2 so basically 2 + 2 + 2

6. -4/3 = 1/1/3 (simplify)

4 0
3 years ago
Read 2 more answers
Given the equation 7(x + 2) = 2x − 1, solve for the variable. Explain each step and justify your process. Jeff solved a similar
Galina-37 [17]
You have to distribute the 7 to x and 2 so :
7x+14=2x-1
Add one to both sides (inverse operations)
7x+14=2x-1
+1 +1
7x+15=2x
Cross Cancel by subtracting 7x from both sides
7x+15=2x
-7x -7x
15=-5x
Divide by -5
15/-5= -5/-5
X= -3

6 0
3 years ago
Write an arithmetic expression that calculates the average of 18 and 46. you may already know that: the average of two numbers i
Masteriza [31]

In this question , we have to write an arithmetic expression that calculates the average of 18 and 46.

TO find the average, we have to add the numbers and divide by 2.

So here we have to add 18 and 46 and divide by 2, that is

d = \frac{18+46}{2} = \frac{64}{2}

And that's the required algebraic expression .

8 0
3 years ago
What is the image of the point (-9,-1) after a rotation of 270 degrees counterclockwise about the origin?
Hunter-Best [27]

Answer:

(-1,9)

Step-by-step explanation:

coortinate point is (-9,-1)

use formula

(x,y)=(y,-x)

(-9,-1)=(-1,9)

3 0
3 years ago
In Which Quadrant is this true
34kurt

Given:

\sin \theta

\tan \theta

To find:

The quadrant in which \theta lie.

Solution:

Quadrant concept:

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II, only \sin\theta and \csc\theta are positive.

In Quadrant III, only \tan\theta and \cot\theta are positive.

In Quadrant IV, only \cos\theta and \sec\theta are positive.

We have,

\sin \theta

\tan \theta

Here, \sin\theta is negative and \tan\theta is also negative. It is possible, if \theta lies in the Quadrant IV.

Therefore, the correct option is D.

5 0
3 years ago
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