All categories

3 years ago

What is the solution set of the equation x²+2x-24=0?

Mathematics

2 answers:

kirill115 [55]3 years ago

5 0

Simple...

you have $x^{2} +2x-24=0$

AND WORK IS ATTACHED!! :D

Montano1993 [528]3 years ago

4 0

The correct answer is x=6

You might be interested in

PLEASE HELP IT IS DUE NOW!!!!<br> will give brainliest

vodomira [7]

Answer:

2.4 = E

-1 4/5 = B

-0.2 =C

-2 3/5 = A

0.6 = D

6. one line under -1

Step-by-step explanation:

5. On the number line each short line is by 2 so basically 2 + 2 + 2

6. -4/3 = 1/1/3 (simplify)

4 0

3 years ago

Read 2 more answers

Given the equation 7(x + 2) = 2x − 1, solve for the variable. Explain each step and justify your process. Jeff solved a similar

Galina-37 [17]

You have to distribute the 7 to x and 2 so :
7x+14=2x-1
Add one to both sides (inverse operations)
7x+14=2x-1
+1 +1
7x+15=2x
Cross Cancel by subtracting 7x from both sides
7x+15=2x
-7x -7x
15=-5x
Divide by -5
15/-5= -5/-5
X= -3

6 0

3 years ago

Write an arithmetic expression that calculates the average of 18 and 46. you may already know that: the average of two numbers i

Masteriza [31]

In this question , we have to write an arithmetic expression that calculates the average of 18 and 46.

TO find the average, we have to add the numbers and divide by 2.

So here we have to add 18 and 46 and divide by 2, that is

$d = \frac{18+46}{2} = \frac{64}{2}$

And that's the required algebraic expression .

8 0

3 years ago

What is the image of the point (-9,-1) after a rotation of 270 degrees counterclockwise about the origin?

Hunter-Best [27]

Answer:

(-1,9)

Step-by-step explanation:

coortinate point is (-9,-1)

use formula

(x,y)=(y,-x)

(-9,-1)=(-1,9)

3 0

3 years ago

In Which Quadrant is this true

34kurt

Given:

$\sin \theta$

$\tan \theta$

To find:

The quadrant in which $\theta$ lie.

Solution:

Quadrant concept:

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II, only $\sin\theta$ and $\csc\theta$ are positive.

In Quadrant III, only $\tan\theta$ and $\cot\theta$ are positive.

In Quadrant IV, only $\cos\theta$ and $\sec\theta$ are positive.

We have,

$\sin \theta$

$\tan \theta$

Here, $\sin\theta$ is negative and $\tan\theta$ is also negative. It is possible, if $\theta$ lies in the Quadrant IV.

Therefore, the correct option is D.

5 0

3 years ago