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3 years ago

What is the solution set? 2x−6>12 Enter your answer in the box.

Mathematics

1 answer:

irina1246 [14]3 years ago

3 0

Yo sup??

2x-6>12

2x>18

x>9

therefore solution set is

x belongs to (9,infinity)

Hope this helps

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3 years ago

What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400. *work needed*

pickupchik [31]

<h3>Answer: x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

Step-by-step explanation:

Given the polynomial equation $x^4-41x^2=-400$ .

Adding 400 on both sides to get rid 400 from right side and set 0 on right side, we get

$x^4-41x^2+400=-400+400$ .

$x^4-41x^2+400=0$ .

Factoring by product sum rule.

We need product of 400 and sum upto -41.

We can see that 400 = -25 × -16 = 400 and -25-16 = -41.

Therefore,

$x^4-25x^2-16x^2+400=0$

Making it into two groups, we get

$(x^4-25x^2)+(-16x^2+400)=0$

Factoring out GCF of each group, we get

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Therefore,

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Applying zero product rule,

x-5=0

x+5=0

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x+4=0.

Therefore,

<h3>x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

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3 years ago

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steposvetlana [31]

The pattern is that every 2 numbers are a pair, the first being any selected number, and the second number next to is the number times 3.

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3 years ago

What is the solution set? ​ 2x−6>12 ​ Enter your answer in the box.

What is the solution set? 2x−6>12 Enter your answer in the box.