Here's a graph of a linear function. Write the equation that describes that function. Express in slope-intercept form.

Mathematics

1 answer:

il63 [147K]2 years ago

3 0

Y=1/3x-1. i’m not sure what point slope is but that’s slope intercept.

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Complex numbers & DeMoivre's theory<br> If z=-1-√3 i and z^6=a+bi, a=_____ and b=_____

Mice21 [21]

Convert $z$ to exponential/polar/trigonometric form:

$r=|z|=\sqrt{(-1)^2+(-\sqrt 3)^2}=2$

$\tan\theta=\dfrac{-\sqrt3}{-1}\implies\theta=\dfrac{4\pi}3$

$\implies z=-1-\sqrt3\,i=2e^{4\pi/3\,i}=2\left(\cos\dfrac{4\pi}3+i\sin\dfrac{4\pi}3\right)$

By DeMoivre's theorem,

$z^6=\left(2e^{4\pi/3\,i}\right)^6=2^6e^{24\pi/3\,i}=64e^{8\pi\,i}$

$z^6=64\left(\cos8\pi+i\sin8\pi)=64$

so that $a=64$ and $b=0$ .

8 0

3 years ago

Which of the following equations represents a line that is perpendicular to

Andreyy89

Answer:

$\large\boxed{y=\dfrac{1}{2}x}$

Step-by-step explanation:

$\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\===============================$

$\text{We have the equation:}\ y=-2x+4\to m_1=-2.\\\\\text{Therefore}\ m_2=-\dfrac{1}{-2}=\dfrac{1}{2}.\\\\\text{We have the equation:}\ y=\dfrac{1}{2}x+b.\\\\\text{Put the coordinate of the point (4, 2) to the equation:}\\\\2=\dfrac{1}{2}(4)+b\\\\2=2+b\qquad\text{subtract 2 from both sides}\\\\0=b\to b=0.\\\\\text{Finally:}\\\\y=\dfrac{1}{2}x$