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lozanna [386]
3 years ago
9

In January Jennifer was allowed to use 150 text messages. If she is allowed to use the same amount of text messages every month.

How many text messages would she have used in all by the month of August?
Mathematics
1 answer:
Firlakuza [10]3 years ago
6 0

She would have used 1200 messages in all by the month of August.

Step-by-step explanation:

Messages allowed per month = 150

There will be 8 months starting from January to August, therefore,

Time period = 8 months

Messages in 8 months = Messages per month * Time period

Messages\ in\ 8\ months=150*8\\Messages\ in\ 8\ months=1200

She would have used 1200 messages in all by the month of August.

Keywords: Multiplication

Learn more about multiplication at:

  • brainly.com/question/629998
  • brainly.com/question/6208262

#LearnwithBrainly

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Answer:

Part 1) Is a exponential growth function

Part 2)  A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}

Part 3) \$6,107.01

Part 4)  \$13,591.41

Step-by-step explanation:

Part 1) What type of exponential model is Natalie’s situation?

What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

P=\$5,000\\r=10\%=0.10  

substitute in the formula above

A=5,000(e)^{0.10t}  

Applying property of exponents

A=5,000(1.1052)^{t}  

therefore

Is a exponential growth function, because the base is greater than 1

Part 2) Write the model equation for Natalie’s situation

A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}

see Part 1)

Part 3) How much money will Natalie have after 2 years?

For t=2 years

substitute

A=5,000(e)^{0.10*2}=\$6,107.01

Part 4) How much money will Natalie have after 10 years?

For t=10 years

substitute

A=5,000(e)^{0.10*10}=\$13,591.41

5 0
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x = y^2 -36

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Add 36 to each side

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Answer:

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