The pythagorean theorem holds for every right triangle: given the legs and the hypothenuse
, the triangle is right if and only if
So, you have to check:
So the first triangle can't be a right triangle.
So the second triangle is a right triangle.
The third triangle can't be right, because it has the same legs but a different hypothenuse
Finally, we have
So the last triangle can't be a right triangle.
Answer:
4th option is correct
Step-by-step explanation:
Answer:
The value of AD=1 and DC=3
Step-by-step explanation:
Given: ΔABC, D∈ AC m∠ABC=m∠BDA, AB=2, AC=4
Diagram: Please find attachment.
To find: AD=? and DC=?
Calculation:
In ΔABC and ΔADB
∠ABC=∠ADB (Given)
∠A=∠A (Common)
Therefore, ΔABC ≈ ΔADB by AA similarity
If two triangles are similar then ratio their corresponding sides are equal
Therefore,
where, AD=?, AB=2, AC=4
AD=1
AD+DC=AC
1+DC=4
DC=4-1
DC=3
Hence, The value of AD=1 and DC=3
Answer:
3 - 48
Step-by-step explanation:
Given
(a + 2)(3a² + 12)(a - 2)
= (a + 2)(a - 2)(3a² + 12) ← expand the first pair of parenthesis using FOIL
=(a² - 4)(3a² + 12) ← expand using FOIL
= 3 + 12a² - 12a² - 48 ← collect like terms
= 3 - 48