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vfiekz [6]
3 years ago
5

4. An isosceles triangle has sides that measure 7cm and 15cm. Find the third side of the

Mathematics
1 answer:
Advocard [28]3 years ago
8 0

Answer:

Third side is 15cm. Perimeter is 37cm.

Step-by-step explanation:

In a triangle sum of two sides is always greater than third side. Two sides of a isosceles triangle are equal.

So if the third side is 7cm

7+7=14cm which is less than 15 cm.

hence third side is 15 cm as

15+15=30cm which is greater than 7cm

15+7=22cm which is greater than 12cm

then

perimeter=15+7+15=37cm

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10 increased by the quotient of a number and 6 is 15
Makovka662 [10]
<h2>Verbal Phrase to Mathematical Phrase</h2><h3>Answer:</h3>

10 +\frac{n}{6} = 15\\

<h3>Step-by-step explanation:</h3>

Let that number be n.

The quotient of a number and 6 is \frac{n}{6}\\.

"Increased" is just another term for "plus (+)" so 10 increased by The quotient of a number and 6 is 10 + \frac{n}{6}\\

And it tells us that it is 15 so it must be 10 +\frac{n}{6} = 15\\

3 0
3 years ago
1. y = x2 + 8x + 15<br> Find the zeros of the function by rewriting the function in intercept form
lubasha [3.4K]

The zeros of given function y=x^{2}+8 x+15 is – 5 and – 3

<u>Solution:</u>

\text { Given, equation is } y=x^{2}+8 x+15

We have to find the zeros of the function by rewriting the function in intercept form.

By using intercept form, we can put value of y as  to obtain zeros of function

We know that, intercept form of above equation is x^{2}+8 x+15=0

\text { Splitting } 8 x \text { as }(5+3) x \text { and } 15 \text { as } 5 \times 3

\begin{array}{l}{\rightarrow x^{2}+(5+3) x+5 \times 3=0} \\\\ {\rightarrow x^{2}+5 x+3 x+5 \times 3=0}\end{array}

Taking “x” as common from first two terms and “3” as common from last two terms

x (x + 5) + 3(x + 5) = 0

(x + 5)(x + 3) = 0

Equating to 0 we get,

x + 5 = 0 or x + 3 = 0

x = - 5 or – 3

Hence, the zeroes of the given function are – 5 and – 3

5 0
3 years ago
➥ The base of a parallelogram is thrice its height. If the area is 897 sq.cm. Find the base and height of the parallelogram.
IgorC [24]

Answer:

The height of parallelogram is 51.87 cm

Step-by-step explanation:

Let The height of a parallelogram = a cm

Then

The base of a parallelogram = 3a cm

So by the given condition

3a×a = 897

3a^2 = 897

a^2 = 897/3

a^2 = 299

a = 17.29

So the height of parallelogram = 3×17.29= 51.87 cm

6 0
3 years ago
What equation does the model represent
lara [203]
5 whole and 1/6 hope it help you
8 0
3 years ago
If M is the midpoint of AB, find the coordinates of A if M(-3, 5) and B(6, -11)
Luden [163]

midpoint= (x, y)

where x=(x1 + x2)/2

y=(y1 + y2)/2

x1=-3, x2=6, y1=5, y2=-11

so x=(-3 + 6)/2= 3/2

y=(5 + -11)/2= (5-11)/2= -6/2= -3

so mid point =(3/2, -3)

hope this helps

7 0
3 years ago
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