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Elina [12.6K]
3 years ago
8

9^2(x-1) = 27^x how do I solve this equation?

Mathematics
1 answer:
serg [7]3 years ago
5 0
Answer: x = 2

Explanation: 9^2x-1 = 3^2 • (2x - 1) = 3^4x-2

27x = 3^3x

Upon equating: 3^4x-2 =3^3x

Since the base is equal , we can equate the powers:

4x - 2 = 3x
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Answer:

Step-by-step explanation:

Remark

The last digit is 1 3 5  7 9 because the last digit is odd.

The first digit must be a 3 because the number is between 300 and 350

Let the first digit = x

Let the second digit = y

Let the third digit = z

x + y = z

x + y + z = 14                        Substitute z for x + y

z + z = 14                              Combine

2z = 14                                  Divide by 2

2z/2 = 14/2                            

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Answer

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Answer:

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Step-by-step explanation:

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Answer:

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