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Andrej [43]
3 years ago
7

How does the structure of the cell membrane help the cell regulate water?

Chemistry
1 answer:
Maslowich3 years ago
6 0
By a process called osmosis. osmosis depends on the concentration of the water inside and outside the cell
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For the following reaction, 5.05 grams of copper are mixed with excess silver nitrate. The reaction yields 11.0 grams of copper(
andreyandreev [35.5K]

Answer:

14.9 g is the ideal yield of Cu(NO₃)₂

Explanation:

Reactants for the reaction: Cu and AgNO₃

Products: Copper nitrate and Ag

The balanced reaction is: Cu(s) + 2AgNO₃(aq) →  2Ag (s) + Cu(NO₃)₂

As the silver nitrate is in excess, the Cu will be the limiting reagent.

We convert the mass to moles → 5.05 g . 1 mol/ 63.55 g = 0.0794 moles

Ratio is 1:1, so 0.0794 moles will produce 0.0794 moles of Cupper(II) nitrate. We convert the moles to mass, and that value will be the theoretical yield.

0.0794 mol . 187.55 g /1 mol =  of Cu(NO₃)₂

8 0
3 years ago
What is the percent by mass of water in Na S04.10H20?
dalvyx [7]

Answer:

                    Percent by mass of water is 56%

Explanation:

                    First of all calculate the mass of hydrated compound as,

Mass of Sodium = Na × 2 = 22.99 × 1 = 45.98 g

Mass of Sulfur = S × 1 = 32.06 × 1 = 32.06 g

Mass of Oxygen = O × 14 = 16 × 14 = 224 g

Mass of Hydrogen = H × 20 = 1.01 × 20 = 20.2 g

Mass of Na₂S0₄.10H₂O = 322.24 g

Secondly, calculate mass of water present in hydrated compound. For this one should look for the coefficient present before H₂O in molecular formula of hydrated compound. In this case the coefficient is 10, so the mass of water is...

Mass of water = 10 × 18.02

Mass of water = 180.2 g

Now, we will apply following formula to find percent of water in hydrated compound,

           %H₂O  =  Mass of H₂O / Mass of Hydrated Compound × 100

Putting values,

                                      %H₂O  = 180.2 g / 322.24 g × 100

                                           %H₂O =  55.92 % ≈ 56%

3 0
3 years ago
A compound is 85.7% C and 14.3% H and has a molar mass of 98g/mol, what is the compounds molecular formula?
vaieri [72.5K]

Answer:

Molecular Formula => (CH₂)₇ => C₇H₁₄      

Explanation:

Empirical ratio is calculated from the sequence...

%/100wt => grams/100wt => moles => mole ratio => reduce mole ratio => Empirical Ratio

C: 85.7% => 85.7g => (85.7/12)mol = 7.14 mole

H: 14.3%  => 14.3g =>     (14.3/1)mol = 14.3 mole

C:H mole ratio => 7.14:14.3

Reduced mole ratio (divide by the smaller mole value) => (7.14/7.14):(14.3/7.14) => Empirical Ratio => 1:2 => Empirical Formula => CH₂

Molecular Wt = Whole No. Multiple of Empirical Formula Wt.

M.Wt = N(Emp Wt) => 98g = N(14g) => N = 7

∴Molecular Formula => (CH₂)₇ => C₇H₁₄

8 0
4 years ago
Read 2 more answers
The ksp of lead(ii) carbonate, pbco3, is 7.40 × 10-14. calculate the solubility of this compound in g/l.
Dennis_Churaev [7]
The  molar  solubility  is  the  Pb ions  present. PbCO3  dissociate  to  form  Pb  ions  and CO3  ions
Ksp  7.40x10^-14 is equal to  (Pb  ions) (CO3 ions)
Pb ions  correspond  to  CO3  ions
(pb ions)( Pb ions) is  equal to 7.40x10^-14
therefore  Pb  ions is square  root  of 7.4x10^14 which  is 2.27x10^-7m
In  
g/l   is (2.27x10^-7) x 267(RFM  of PbCO3) which  is  6.06x10^-5 g/l
5 0
3 years ago
Producer gas is a fuel formed by passing air over red-hot coke (amorphous carbon). What mass of a producer gas that consists of
Karolina [17]

Producer gas is a fuel that is produced by burning biomass with an air deficit passed over red-hot coke (amorphous carbon). This gas is nothing but a mixture of gases such as hydrogen (H), carbon monoxide (CO), carbon dioxide (CO₂) and nitrogen (N₂).

The equation of producer gas is as follows -

                            CO₂ + 2N₂ (air) → CO + 2N₂

                            ΔH = -27.06 kcal

We know that,

1 Ton = 1000 kg

Mass of coke needed to form producer gas = 1.75 tons = 1750 kg

Given values,

Carbon monoxide (CO) = 25%  

Carbon dioxide (CO₂) = 5%

Nitrogen (N₂) = 70%

One mole of carbon dioxide reacts with two moles of nitrogen to form one mole of carbon monoxide and nitrogen (producer gas).

We know that, 1 ton (1000 kg) of coke produces 470 Nm³ of producer gas, i.e.

470 × 4.359 = 2048.73 kg

1000 kg of coke produces = 2048.73 kg of producer gas

∴ 1 kg of coke produces = 2048.73 ÷ 1000 kg of producer gas

∴ 1750 kg of coke produces = 2048.73 × 1750 / 1000 = 3585.28 kg of producer gas.

Percentage yield = 87%

                             = 3585.28 × 87/100

                             = 3119.19 kg of producer gas

                             = 3.44 tons

Learn more about coke here-

brainly.com/question/13105289

#SPJ4

7 0
2 years ago
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