Campare how the structure and function of a plant is similar to the human body

Compare the solubility of silver iodide in each of the following aqueous solutions:

Semenov [28]

Answer:

Compare the solubility of silver iodide in each of the following aqueous solutions:

a. 0.10 M AgCH3COO

b. 0.10 M NaI

c. 0.10 M KCH3COO

d. 0.10 M NH4NO3

1. More soluble than in pure water.

2. Similar solubility as in pure water.

3. Less soluble than in pure water.

Explanation:

This can be explained based on common ion effect.

According to common ion effect the solubility of a sparingly soluble salt decreases further in a solution which has a common ion to it.

The solubility of AgI(s) silver iodide in water is shown below:

$AgI(s) Ag^{+}(aq)+I^{-}(aq)\\$

a. a. 0.10 M AgCH3COO has a common ion Ag+ with AgI.

So, AgI is less soluble than in pure water in this solution.

b. 0.10 M NaI has a common ion I- with AgI.

So, AgI is less soluble than in pure water in this solution.

c. 0.10 M KCH3COO:

This solution has no common ion with AgI.

So, AgI has similar solubility as in pure water.

d. 0.10 M NH4NO3:

In this solution, AgI can be more soluble than in pure water.

7 0

3 years ago

(a) Kw = 1.139 × 10⁻¹⁵ at 0°C and 5.474 × 10⁻¹⁴, find [H₃O⁺] and pH of water at 0°C and 50°C.

kondor19780726 [428]

The value of [H₃O⁺] and pH of water at 0°C and 50°C.

0°C value of [H₃O⁺] = 3.375 x 10⁻⁸

50°C value of [H₃O⁺] = 2.340 x 10⁻⁷

pH of water at 0°C = pH = 7.4717

pH of water at 50°C = pH = 6.6308

<h3>pH of water at different level:</h3>

Water with a pH less than 7 is considered acidic, while water with a pH greater than 7 is considered basic. The normal pH range for surface water systems is 6.5 to 8.5, and for groundwater systems is 6 to 8.5. Alkalinity is a measure of a water's ability to withstand a pH change that would cause it to become more acidic.

<h3>According to the given information:</h3>

0°C = Kw = 1.139 × 10⁻¹⁵

50°C = 5.474 × 10⁻¹⁴

Solving at 0°C for [H₃O⁺] and pH. water is neutral therefore its[H₃O⁺] [OH⁻]

are equal [H₃O⁺] = [OH⁻].

Kw = [H₃O⁺] [OH⁻]

Kw = [H₃O⁺]²

[H₃O⁺] = √Kw

= √1.139 × 10⁻¹⁵

= 3.375 x 10⁻⁸

pH = -log[H₃O⁺]

= -log 3.375 x 10⁻⁸

= 7.4717

Solving at 50°C for [H₃O⁺] and pH. water is neutral therefore its[H₃O⁺] [OH⁻]

are equal [H₃O⁺] = [OH⁻].

Kw = [H₃O⁺] [OH⁻]

Kw = [H₃O⁺]²

[H₃O⁺] = √Kw

= √ 5.474 × 10⁻¹⁴

= 2.340 x 10⁻⁷ M

pH = -log[H₃O⁺]

= -log2.340 x 10⁻⁷

pH = 6.6308

The value of [H₃O⁺] and pH of water at 0°C and 50°C.

0°C value of [H₃O⁺] = 3.375 x 10⁻⁸

50°C value of [H₃O⁺] = 2.340 x 10⁻⁷

pH of water at 0°C = pH = 7.4717

pH of water at 50°C = pH = 6.6308

To know more about pH of water visit:

brainly.com/question/13822050

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I understand that the question you are looking for is:

Kw = 1.139 × 10⁻¹⁵ at 0°C and 5.474 × 10⁻¹⁴, find [H₃O⁺] and pH of water at 0°C and 50°C. find the [H₃O⁺] and pH of water at 0°C and 50°C.

3 0

1 year ago

I have 26 protons,26 electrons, and 30 neutrons?

Amiraneli [1.4K]

Answer:

Iron (Fe)

Explanation:

# of protons is the atomic number of the element

the element with the atomic number 26 is Iron

with 26 electrons this means it is Iron with no charge

with 30 neutrons this means the atomic weight will be

26 (protons) + 30 (neutrons) = 56

the real atomic weight of iron listed on the periodic table is 55.845, this rounded up is 56.

7 0

3 years ago

When 4.21 grams of potassium hydroxide are added to 250 mL of water in a coffee cup calorimeter, the temperature rises by 4.14°C

Schach [20]

Answer:

The molar heat of solution of potassium hydroxide = 57.7 kJ /mol

Explanation:

<u>Step 1:</u> Data given

Mass of potassium hydroxide = 4.21 grams

Volume of water = 250 mL

Temperature rise = 4.14 °C

Density = 1g/mL

Specific heat = 4.184 J/g°C

<u>Step 2:</u> Calculate the heat absorbed by water

q = m*c*ΔT

⇒ with m = the mass of water = 250 grams

⇒ with c= the specific heat of the solution = 4.184 J/g°C

⇒ with ΔT = 4.14 °C

q = 250 * 4.184*4.14 = 4330.4 J

<u>Step 3:</u> Calculate moles of KOH

Moles KOH = Mass KOH / Molar mass KOH

Moles KOH = 4.21 grams / 56.106 g/mol

Moles KOH = 0.075 moles

<u>Step 4:</u> Calculate molar heat of solution

4330.4 J / 0.075 moles = 57738.7 j/mol = 57.7 kJ /mol

(Note that the enthalpy change for the reaction is negative because the reaction is exothermic)

The molar heat of solution of potassium hydroxide = 57.7 kJ /mol

6 0

4 years ago

Which of these statements is true about photons?

Yuliya22 [10]

Answer: it’s a I believe

Explanation: protons are smaller then atoms which means they have less mass

6 0

3 years ago