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Elena L [17]
2 years ago
12

This question is about salts.

Chemistry
1 answer:
frez [133]2 years ago
7 0

Here is the three observation about copper.

<h3>What is copper?</h3>

copper (Cu), chemical element, a reddish, extremely ductile metal of the  Group 11 (Ib) of the periodic table that is an unusually by its  good conductor of to the  electricity and heat. Copper of  to the found in the free metallic state in nature. This is  native copper was first by the  used .

The reaction between to the  copper carbonate and it is  sulphuric acid will be a great neutralization reaction. Copper carbonate will acts like as a base, however, sulphuric acid is an acid. This reaction can also be the  viewed as a double line displacement reaction too. By it's understand the nature of this reaction and what will be the final to  product of this reaction.

To know more about copper click-

brainly.com/question/26449005

#SPJ1

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Enter your answer in the box provided. How many grams of helium must be added to a balloon containing 6.24 g helium gas to doubl
Archy [21]

Answer : The mass of helium gas added must be 12.48 grams.

Explanation : Given,

Mass of helium (He) gas = 6.24 g

Molar mass of helium = 4 g/mole

First we have to calculate the moles of helium gas.

\text{Moles of }He=\frac{\text{Mass of }He}{\text{Molar mass of }He}=\frac{6.24g}{4g/mole}=1.56moles

Now we have to calculate the moles of helium gas at doubled volume.

According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,

V\propto n

or,

\frac{V_1}{V_2}=\frac{n_1}{n_2}

where,

V_1 = initial volume of gas  = V

V_2 = final volume of gas = 2V

n_1 = initial moles of gas  = 1.56 mole

n_2 = final moles of gas  = ?

Now we put all the given values in this formula, we get

\frac{V}{2V}=\frac{1.56mole}{n_2}

n_2=3.12mole

Now we have to calculate the mass of helium gas at doubled volume.

\text{Mass of }He=\text{Moles of }He\times \text{Molar mass of }He

\text{Mass of }He=3.12mole\times 4g/mole=12.48g

Therefore, the mass of helium gas added must be 12.48 grams.

4 0
3 years ago
1.
guajiro [1.7K]

Answer:

The flask would probably feel cooler than before the reaction started.

Reasoning:

Endothermic is a process or reaction accompanied by or requiring the absorption of heat

3 0
4 years ago
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