<span>Answer:
H-C-N H-N-C C-H-N
Notice that C-H-N is the same as N-H-C just written backwards. ( i.e. they have the same connectivtiy.) You can exclude the last one with H in the middle since H has two bonds and 4 electrons around it. At this point you couldn't differentiate between the first two, so I would give you the connectivity in such a problem, which in this case is H-C-N.</span>
Explanation:
I can give you some examples;
1) water
2) biomass
3)Soil
4) forest...
I hope this will help you
Answer: The standard entropy of vaporization of ethanol is 0.275 J/K
Explanation:
![C_2H_5OH(l)\rightleftharpoons C_2H_5OH(g)](https://tex.z-dn.net/?f=C_2H_5OH%28l%29%5Crightleftharpoons%20C_2H_5OH%28g%29)
Using Gibbs Helmholtz equation:
![\Delta G=\Delta H-T\Delta S](https://tex.z-dn.net/?f=%5CDelta%20G%3D%5CDelta%20H-T%5CDelta%20S)
For a phase change, the reaction remains in equilibrium, thus ![\Delta G=0](https://tex.z-dn.net/?f=%5CDelta%20G%3D0)
![\Delta H=T\Delta S](https://tex.z-dn.net/?f=%5CDelta%20H%3DT%5CDelta%20S)
Given: Temperature = 285.0 K
![\Delta H=78.3J/mol](https://tex.z-dn.net/?f=%5CDelta%20H%3D78.3J%2Fmol)
Putting the values in the equation:
![78.3J=285.0K\times \Delta S](https://tex.z-dn.net/?f=78.3J%3D285.0K%5Ctimes%20%5CDelta%20S)
![\Delta S=0.275J/K](https://tex.z-dn.net/?f=%5CDelta%20S%3D0.275J%2FK)
Thus the standard entropy of vaporization of ethanol is 0.275 J/K
Answer:
In our Sun, as in other stars, roughly 99.9% or so of all light emitted is emitted in a thin layer known as the photosphere, or light sphere. This is explained as follows. Interior to the photosphere the gas is ever denser and becomes far too opaque for any photon to emerge directly from that layer.
Explanation: