Answer:
0.897 J/g°C
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Mass (M) of substance = 155g
Initial temperature (T1) = 25.0°C
Final temperature (T2) = 40°C
Change is temperature (ΔT) = T2 – T1 = 40°C – 25.0°C = 15°C
Heat Absorbed (Q) = 2085 J
Specific heat capacity (C) of the substance =?
Step 2:
Determination of the specify heat capacity of the substance.
Applying the equation: Q = MCΔT, the specific heat capacity of the substance can be obtained as follow:
Q = MCΔT
C = Q/MΔT
C = 2085 / (155 x 15)
C = 0.897 J/g°C
Therefore, the specific heat capacity of the substance is 0.897 J/g°C
Answer:
D. all of the above.
Explanation:
The kinetic-molecular theory of gases suggests that; the particles of a gas move independently of each other, the particles in a gas move rapidly, the particles in a gas are far apart.
Hope it helps.
Answer:
According to Coulomb’s law, the Ca and Se ions have 4 times the attractive force (2+ × 2-) than that of the K and Br ions (1+ × 1-).
Explanation:
From Coulomb's law, the attractive force between calcium and selenium ions is four times the attractive force between potassium and bromide ions.
This has something to do with size and magnitude of charge. Calcium ions and selenide ions are smaller and both carry greater charge magnitude than potassium and bromide ions. This paves way for greater electrostatic attraction between them when the distance of the charges apart is minimal. Hence a greater lattice energy.
Answer:
Explanation:
We can calculate the volume of the oxygen molecule as the radius of oxygen molecule is given as 2×10⁻¹⁰m.
We know that volume=4/3×πr³
volume =4/3×π(2.0×10⁻¹⁰m)³
volume=33.40×10⁻³⁰m³
Volume of oxygen molecule=33.40×10⁻³⁰m³
we know the ideal gas equation as:
PV=nRT
k=R/Na
R=k×Na
PV=n×k×Na×T
n×Na=N
PV=Nkt
p is pressure of gas
v is volume of gas
T is temperature of gas
N is numbetr of molecules
Na is avagadros number
k is boltzmann constant =1.38×10⁻²³J/K
R is real gas constant
So to calculate pressure using the formula;
PV=NkT
P=NkT/V
Since there is only one molecule of oxygen so N=1
P=[1×1.38×10⁻²³J/K×300]/[33.40×10⁻³⁰m³
p=12.39×10⁷Pascal
